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Vikki
9 days ago
6

What can each term of the equation be multiplied by to eliminate the fractions before solving? x – + 2x = StartFraction one-half

EndFraction x minus StartFraction 5 Over 4 EndFraction plus 2 x equals StartFraction 5 Over 6 EndFraction plus x. + x 2 6 10 12
Mathematics
2 answers:
zzz [4K]9 days ago
6 0

Solution: when addressing an equation that includes fractions, we remove the fractions by multiplying through by the Least Common Denominator (LCD) of all denominators present. The LCD represents the smallest common denominator. For this case, we first determine the Least Common Multiple (LCM) of the numbers 2, 4, and 6, which will help us find the LCD.

2=2

4=2·2

6=2·3

LCM = 2·2·3

LCM = 12

This means that we need to multiply each term in the equation by 12 in order to eliminate the fractions and proceed with solving the equation.

12

Inessa [3.8K]9 days ago
3 0

The correct answer to your inquiry is 12, or alphabetically D. Hope this information proves helpful, and have a wonderful day!

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6 days ago
Laila wants to create a data display to clearly show the median salary, the highest salary,
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A box plot

Step-by-step explanation:

Assuming there are 685 employees in her organization

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7 0
17 days ago
Read 2 more answers
The University of Central Florida's cheerleading team has eighteen males and twenty-one females. If h represents the height of a
Leona [4145]

Answer:

The range of cheerleaders' heights lies within the interval [58, 74)

It includes all real numbers from 58 inches and above, but below 74 inches.

Step-by-step explanation:

we have

260 \leq 4h+28

Separate the combined inequality into two distinct inequalities

260 \leq 4h+28 -----> inequality A

4h+28 -----> inequality B

Solve inequality A

260 \leq 4h+28

Subtract 28 from both sides

232 \leq 4h

Split by 4 on both sides

58 \leq h

Reformulate

h \geq 58\ in

Address inequality B

4h+28

Subtract 28 from both sides

4h

Split by 4 on both sides

h

consequently

The height range of the cheerleaders is the interval [58, 74)

It consists of every real number starting from 58 inches and less than 74 inches

3 0
6 days ago
Starting from 300 feet away, a car drives toward you. It then passes by you at a speed of 48 feet per second.The distance d (in
Zina [3893]
From a distance of 300 feet, a car approaches you at a speed of 48 feet per second. The distance d (in feet) of the car from you after t seconds can be described by the equation ​d=|300−48t|​. At what moments does the car find itself 60 feet away from you?
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5 days ago
Finally, suppose m1→∞, while m2 remains finite. what value does the the magnitude of the tension approach?
AnnZ [3868]
The tension does not approach infinity.
<span>Let's analyze free body diagrams (FBDs) for each mass, considering the direction of motion of m₁ as positive.

For m₁: m₁*g - T = m₁*a

For m₂: T - m₂*g = m₂*a

Assuming a massless cord and pulley without friction, the accelerations are the same.

From the second equation: a = (T - m₂*g) / m₂

Substitute into the first:
m₁*g - T = m₁ * [(T - m₂*g) / m₂]
Rearranging:
m₁*g - T = (m₁*T)/m₂ - m₁*g
2*m₁*g = T * (1 + m₁/m₂)
2*m₁*m₂*g = T * (m₂ + m₁)
T = (2*m₁*m₂*g) / (m₂ + m₁)
Taking the limit as m₁ approaches infinity:
T = 2*m₂*g

This aligns with intuition since the greatest acceleration m₁ can have is -g. The cord then accelerates m₂ upward at g while gravity acts downward, leading to a maximum upward acceleration of 2*g for m₁.</span>
5 0
14 days ago
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