N example 5.4 and exercise 5.5, we considered the joint density of y1, the proportion of the capacity of the tank that is stocke

Answer: 0.1289

Step-by-step explanation:

Given: The proportion of students absent on Mondays at a large university.:

Sample size:

Mean:

Standard deviation =

Let x represent a binomial variable.

Referencing the standard normal distribution table,

(1)

Z score for normal distribution:-

For x=4

For x=3

Thus, from (1)

Consequently, the likelihood of four students being absent =

A) The cost to send a package that weighs 3.2 pounds is $4.13. Since this weight exceeds 3 pounds but remains below 4 pounds, we have to refer to the pricing that applies to 4-pound packages (see the attached document for pricing details).

b) To illustrate the Media Mail shipping costs based on the weight of the books, a line graph is appropriate. In this graph, the weight in pounds is represented on the x-axis and the shipping costs on the y-axis.

c) The graph depicting the Media Mail shipping costs as a function of book weight will be represented by the equation: f(x) = 2.69 + 0.48(x-1)

Answer:

a. 0.82%

b. 71.11%

c. 0.564 micrometer

Step-by-step explanation:

To find the z value for each measurement, we must calculate and determine the percentage they correspond to, and the difference will give us the percentage between those two statistics.

The equation for z is:

z = (x - m) / (sd)

Here, x is the value being evaluated, m denotes the mean, and sd represents the standard deviation.

a.

For 0.62 copies, we calculate:

z = (0.62 - 0.5) / (0.05)

z = 2.4

This translates to 0.9918.

Therefore, p (x > 0.62) = 1 - 0.9918

p (x > 0.62) =  0.0082 = 0.82%

b.

For 0.47 copies, we have:

z = (0.47 - 0.5) / (0.05)

z = -0.6, which equates to 0.2742.

For 0.63 copies:

z = (0.63 - 0.5) / (0.05)

z = -2.6, which yields 0.9953.

Hence, p (0.47 > x > 0.63) = 0.9953 - 0.2742

p (0.47 > x > 0.63) = 0.7211 = 72.11 %

c.

For x copies, we find:

p = 0.9 corresponds to z = 1.28.

Thus, 1.28 = (x - 0.5) / (0.05)

From which we derive:

x = 1.28*0.05 + 0.5

x = 0.564 micrometer

Answer:

89

Step-by-step explanation:

Given that

2 O, 2 T and 1 M

Now based on this, the following arrangements exist  

1

Three arrangements i.e. {M,T,O}

2

XX or XY

XX in 2C1 = two arrangements i.e. {OO or TT}

XY in 3C2 × 2! = six arrangements

3

XXY or XYZ

XXY in 2C1 × 2C1 × 3! ÷ 2! = twelve arrangements

XYZ in 3C3 × 3! = six arrangements

4

XXYY or XXYZ

XXYY = 4! ÷ (2! × 2!) = six arrangements

XXYZ in 2C1 ×  4! ÷ 2! = twenty four arrangements

5

= 5! ÷ (2! ×2!)

= 120 ÷ 4

= 30

Thus, the overall total is

= 3 + (2 +6)+ (12 +6) + (6 +24) + 30

= 89

As a fraction, 2.161616 is represented as 2 161616/1000000, and when simplified, it becomes 2 10101/62500.