Answer:
B
Step-by-step explanation:
A. (1, 2), (1,-2), (3, 2), (3, 4)
B. (1,6), (2, 7),(4,9), (0,5)
C. (0, 2), (2,3), (0, -2), (4,1)
D. (2, 4), (0, 2), (2, - 4), (5,3)
There are no x values that appear more than once.
The solution to the equation is 40
This indicates the max number of wedding invitations they can afford to send within their budget.
To find the zero of the function, we set the dependent variable (here, m) to zero.
So we have;
0 = 50-1.25w
1.25w = 50
w = 50/1.25
w = 40
What implication does this have in this context?
Essentially, it means that the couple can send out invitations to a total of 40 people based on their budget.
Response:
a. 0.76
b. 0.23
c. 0.5
d. p(B/A) signifies the likelihood that a student with a visa card also possesses a MasterCard.
p(A/B) indicates the probability that a student with a MasterCard also has a visa card.
e. 0.35
f. 0.31
Detailed explanation:
a. p(AUBUC) = P(A) + P(B) + P(C) - P(AnB) - P(AnC) - P(BnC) + P(AnBnC)
= 0.6 + 0.4 + 0.2 - 0.3 - 0.11 - 0.1 + 0.07 = 0.76
b. P(AnBnC') = P(AnB) - P(AnBnC)
= 0.3 - 0.07 = 0.23
c. P(B/A) = P(AnB)/P(A)
= 0.3/0.6 = 0.5
e. P((AnB)/C) = P((AnB)nC)/P(C)
= P(AnBnC)/P(C)
= 0.07/0.2 = 0.35
f. P((AUB)/C) = P((AUB)nC)/P(C)
= (P(AnC) U P(BnC))/P(C)
= (0.11 + 0.1)/0.2
= 0.21/0.2 = 0.31
First, it's essential to define the equation that characterizes the function.
The investment is $200 with an interest rate of 5%, where y represents the money after x periods.
After one period, the amount of money grows to 200 plus 5% interest, resulting in 200 + 5%(200) = 200 (1 +5%) = 200 (1 + 0.05) = 200 (1.05)
After two periods, the total is 200(1.05)*(1.05) = 200 (1.05)^2
After three periods, it will be 200 (1.05)^3
Consequently, it can be inferred that after x periods, y = 200 (1.05)^x
Next, this function can be analyzed to project the graph's shape and significant points.
The answers derive from the initial value and the growth factor.
The initial value occurs when x = 0, giving y = 200 (1.05)^0 = 200*1 = 200
The growth factor is 1.05, indicating each subsequent value is multiplied by 1.05.