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Lynna
10 days ago
10

.1.In a large bag of marbles, 25% of them are red. A child chooses 4 marbles from this bag. If the child chooses the marbles at

random, what is the chance that the child gets exactly three red marbles? . A) 0.047. B) 0.141 . C) 0.211 . D) 0.063. . 2.A pet supplier has a stock of parakeets of which 10% are blue parakeets. A pet store orders 3 parakeets from this supplier. If the supplier selects the parakeets at random, what is the chance that the pet store gets exactly one blue parakeet?. A) 0.081 . B) 0.243 . C) 0.027 . D) 0.003 . In a large bag of marbles, 25% of them are red. A child chooses 4 marbles
Mathematics
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In the diagram, DG = 15, GF = 5, EH = 12, and DE = 8. To prove that △DFE ~ △GFH by the SSS similarity theorem using the informat
lawyer [12517]

Answer: C) HF measures 4 units and GH is 2 units.

Step-by-step explanation:

The SSS similarity theorem asserts that triangles are similar if the lengths of their corresponding sides are in proportion.

For triangles ΔDFE and ΔGFH:

DG equals 15, GF is 5, EH equals 12, and DE is 8.

To demonstrate the similarity of ΔDFE and ΔGFH according to the SSS similarity theorem, we require:

\frac{DF}{GF}=\frac{FE}{FH}=\frac{DE}{GH}\\\\\Rightarrow\frac{DG+GF}{GF}=\frac{FH+EH}{FH}=\frac{DE}{GH}\\\\\Rightarrow\frac{5+15}{5}=\frac{12+HF}{FH}=\frac{8}{GH}\\\\\Rightarrow\frac{20}{5}=\frac{12+HF}{FH}\ and\ \frac{20}{5}=\frac{8}{GH}\\\\\Rightarrrow4HF=12+HF\ and\ GH=\frac{8}{4}\\\\\Rightarrow3HF=12\ and\ GH=2\\\\\Rightarrow HF=4\ and\ GH=2

Thus, to confirm that △DFE is similar to △GFH utilizing the SSS similarity theorem and the data from the diagram, it is essential to establish that HF measures 4 units and GH measures 2 units.

5 0
2 months ago
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Employee C is paid an hourly rate of $13.25 per hour and works 2,080 hours per year. The employee was just promoted and received
Svet_ta [12734]
His hourly wage was $13.25, and he just got a 15% increase.
Calculating: 13.25 + 0.15 × 13.25 = 13.25 + 1.99 = 15.24 dollars per hour with the raise.

For 2080 hours, the total yearly pay is:
15.24 × 2080 = 31,699.20 <==
4 0
3 months ago
Read 2 more answers
The table shows the estimated number of lines of code written by computer programmers per hour when x people are working. A 2-co
tester [12383]

Answer:

Crearemos una tabla con estos valores según diferentes valores de x.

x                  A                 B                C               D

2              66.66          49.3            52.5           50

4             94.57            71.44           106.3         104  

6             134.14           103.57         160.1          158

8             190.27        150.14          213.9         212

10           269.91           217.64         267.7         266

12           382.85          315.5           321.5          320.

Por lo tanto, la función que mejor representa los datos es:

Opción C.

y=26.9x-1.3

Explicación paso a paso:

4 0
3 months ago
What is the quotient (2x4 – 3x3 – 3x2 + 7x – 3) ÷ (x2 – 2x + 1)?
Inessa [12570]

Answer:

Quotient: 2x^2+x-3

Refer to the attached document.

Step-by-step explanation:

Provided: (2x^4-3x^3-3x^2+7x-3)\div (x^2-2x+1)

A rational expression is provided, and we need to compute the quotient.

We will utilize long division to obtain the quotient.

Initially, we eliminate 2x^4 by x^2

x^2-2x+1 ) 2x^4-3x^3-3x^2+7x-3 ( 2x^2+x-3

-2x^4+4x^3-2x^2

x^3-5x^2+7x

-x^3+2x^2-x

-3x^2+6x-3

3x^2-6x+3

0

Thus, the result of the division is 2x^2+x-3

8 0
1 month ago
Read 2 more answers
While on vacation in Canada, you notice that temperatures are reported in degrees Celsius. You know there is a linear
zzz [12365]

Given that the relationship is linear.

The equation can be expressed as y = mx + c.

Substituting, when x = 0, we have y = 32.

Thus, 32 = c.......( 1 )

Then, when x = 100, y results in 212.

Which gives us:

212 = 100m + c.......( 2 )

By equating equations 1 and 2, we obtain:

100m = 212 - 32

Solving for x yields 1.8.

The final equation is therefore y = 1.8x + 32.

Hence, this represents the required solution.

7 0
2 months ago
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