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Dmitry
20 days ago
11

In pea plants, the allele for tall stalks (T) is dominant over the allele for short stalks (t). Suppose a cross between a tall p

ea plant and a short pea plant produces 43 tall offspring and 47 short offspring. If one of the tall offspring is crossed with one of the short offspring, what ratio of genotypes would be most likely in their offspring
Biology
2 answers:
inysia [1.6K]20 days ago
6 0

Answer:

The ratio will be equal, in a 1:1 proportion.

Explanation:

Assuming the dominant allele TT is crossed with the recessive short stalk (tt).

The F1 generation shows    Tt, Tt, Tt, Tt.

When a heterozygous dominant (Tt) is crossed with the homozygous recessive (tt):

Then in F2:

Tt, Tt = 2; tt, tt = 2

This results in 2:2, which reduces to 1(Tt):1(tt) when simplified to the lowest whole numbers.

enyata [1.7K]20 days ago
6 0

Answer:

Tt - 1/2

tt - 1/2

Explanation:

The outcome of crossing a tall pea plant with a short pea plant, resulting in 43 tall and 47 short offspring (approaching a 1:1 ratio), likely involves a heterozygous tall plant crossed with a homozygous short plant.

Tt   x   tt

Offspring = Tt   Tt   tt   tt (50% tall and 50% short)

If we cross a tall offspring (Tt) with a short offspring (tt):

Tt   x   tt

Offspring = Tt   Tt   tt   tt

Genotype ratio = 2Tt:2tt

<ptherefore>

Tt = 1/2

tt = 1/2

</ptherefore>
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