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Rina8888
2 months ago
12

Find the derivative of the vector function r(t)=ta×(b+tc), where a=⟨2,−3,4⟩, b=⟨−4,5,−1⟩, and c=⟨−2,−1,5⟩.

Mathematics
1 answer:
lawyer [12.5K]2 months ago
7 0

Answer:

la derivada de la función vectorial dada es = ( -16-22t, 14-36t, -2-16t )

Explicación paso a paso:

datos proporcionados:

función vectorial: r(t) = ta*(b+tc)

a = ( 2,-3.4).   b = (-4,5,-1).  c = ( -2,-1,5)

para determinar la derivada de la función vectorial, se procederá a diferenciar respecto a x; aquí está la solución detallada

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Let RS be denoted as y.

Given that T is the midpoint of RS, this results in RT = TS = \frac{y}{2}

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Given that Z is the midpoint of WS.

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However, TZ is defined as x.

Thus, \frac{y}{8} = x

y = 8x = RS.

A) Length of RW = \frac{y}{4} = \frac{8x}{4} = 2x

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An image is provided for clarification.

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Respuesta:

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