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podryga
1 month ago
10

Consider the discussion in our Devore reading in this unit involving an important distinction between mean and median that uses

the concept of a trimmed mean to highlight an important continuum between the two. Presuming that the mean and median are different values for a distribution, the mean can be taken to indicate a 0% trim, and the median can be taken to approach a 50% trim (with effectively 100% of the values removed). These two values define a continuum of trimmed mean values that would fall between the two. Discuss why the mean and median of the distribution always approach each other as we take trimmed means at higher and higher percentages (e.g., 10%, 20%, 30% ...). In particular, describe what is happening to the kurtosis and skewness of the distribution as we trim off more and more data. Speculate on whether or not you might expect to see an optimum point in that process at some value between the mean and median. (Hint: You should!) Why might this matter?
Mathematics
1 answer:
Leona [12.6K]1 month ago
3 0

Answer:

Step-by-step explanation:

A trimmed mean is a statistical averaging technique that eliminates a small specified percentage of both the highest and lowest values before computing the average. Once the designated data points are removed, the trimmed mean is calculated using a standard arithmetic average formula. Employing a trimmed mean helps reduce the impact of extreme data points that could distort the traditional mean.

Trimmed means yield a more accurate representation of the central tendency of the majority of observations compared to the mean, particularly when sampling from skewed distributions;

the standard error associated with the trimmed mean is less influenced by outliers and asymmetry than the mean, allowing tests based on trimmed means to potentially exhibit greater statistical power than those relying on the mean.

When utilizing a trimmed mean in an inferential test, we draw conclusions about the population trimmed mean rather than the overall population mean. This principle holds true for the median or any other measure of central tendency.

While one may stipulate various skewness values, they often result from a handful of outliers, with the trimmed skewness remaining as such.

There's limited practical use for trimmed skewness or kurtosis, partly due to circumstances where

the skewness and kurtosis are greatly dependent on outliers, making them less effective measures, thus, trimming offers a solution by bypassing these issues.

Challenges related to complex distribution shapes are frequently best addressed by applying transformations.

Alternative methods exist for measuring or broadly evaluating skewness and kurtosis, such as the previously mentioned technique or L-moments. Since a skewness measure (mean? median) / SD is straightforward but often overlooked, it can be quite beneficial, primarily since it remains bounded within [?1,1][?1,1].

I anticipate identifying the optimal point during that process at some point between the mean and median.

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Triangle SRQ undergoes a rigid transformation that results in triangle VUT. 2 right triangles with identical side lengths and an
babunello [11817]

Answer:

The accurate statements are 2 and 3.

Step-by-step explanation:

Triangle SRQ undergoes a rigid transformation resulting in triangle VUT

Thus, ΔSRQ ≅ ΔVUT

Consequently, point S maps to point V, point R corresponds with point U, and point Q corresponds with point T.

Based on this information, let's review the statements:

1) SQ corresponds to VU. False as SQ corresponds to VT

2) ∠R corresponds to ∠U. True

3) UV corresponds to RS. True

4) ∠S corresponds to ∠T.  False since ∠S corresponds to ∠V

5) QS corresponds to RS. False since QS corresponds to TV

Therefore, the true statements are 2 and 3.

2) ∠R corresponds to ∠U

3) UV corresponds to RS.

6 0
11 days ago
You need to haul a load of patio bricks to a job site. each brick weighs 4 pounds 14 ounces. your truck can carry a 3/4-ton load
PIT_PIT [12445]
To solve this problem, we need to convert the measurements so we can carry out the necessary calculations. A ton equals 2000 pounds, therefore, 3/4 ton translates to 1500 pounds. Since there are 16 ounces in a pound, 4 pounds and 14 ounces amounts to 4.875 pounds. To find the number of bricks, we divide:
                                     number of bricks = 1500 lbs / 4.875 lbs
                                                            = 307.7

Consequently, this is the number of bricks required. The final answer is approximately.
6 0
1 month ago
What is a rational number that is located between 31.5 and 31.6
Svet_ta [12734]
A rational number refers to any number that can be written as a fraction, such as 2, -3, 2/3, etc.

Essentially, any non-repeating number found between 31.5 and 31.6 would suffice.

Examples include: 31.51, 31.52, 31.568, 31.599

I suggest 31.55 since it’s straightforward and can be expressed as the fraction: 361/20

4 0
1 month ago
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Jessica is asked to write a quadratic equation to represent a function that goes through the point (8, –11) and has a vertex at
PIT_PIT [12445]

the answer is c. I completed the review

5 0
29 days ago
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One sphere has a radius of 5.10 cm; another has a radius of 5.00cm. What is the difference in volume (in cubic centimeters) betw
lawyer [12517]
\bf \textit{volume of a sphere}\\\\
V=\cfrac{4\pi r^3}{3}\qquad 
\begin{cases}
r=radius\\
-----\\
r_1=5.10\\
r_2=5
\end{cases}\implies \cfrac{V_1}{V_2}\implies \cfrac{\frac{4\pi \cdot 5.10^3}{3}}{\frac{4\pi \cdot 5^3}{3}}
\\\\\\
\cfrac{\underline{4\pi }\cdot 5.10^3}{\underline{3}}\cdot \cfrac{\underline{3}}{\underline{4\pi }\cdot 5^3}\implies \cfrac{5.10^3}{5^3}\implies \cfrac{132.651}{125}
5 0
1 month ago
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