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Harrizon
2 months ago
12

Draw a model to represent the problem 12 divided by 6

Mathematics
2 answers:
PIT_PIT [12.4K]2 months ago
7 0

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Zina [12.3K]2 months ago
5 0

The issue can be represented in various models.
For instance, we can illustrate 12 counters (represented as circles) distributed into six boxes (represented as squares).
Each box contains two circles.

Refer to the diagram below for the model.

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How much profit was generated by the sales of gold label and black label combined?
lawyer [12517]
The profit produced by combining sales of gold label and black label equals the total of their individual profits. From the table \begin{array}{ccc}&\text{Number of bottles sold}&\text{Average profit (per bottle)}\\\text{Gold label}&1,000&\$2.75\end{array} you find the gold label's profit 1,000\cdot \$2.75=\$2,750. and similarly from another table \begin{array}{ccc}&\text{Number of bottles sold}&\text{Average profit (per bottle)}\\\text{Black label}&2,000&\$1.50\end{array} find the black label's profit 2,000\cdot \$1.50=\$3,000.. Adding these yields \$2,750+\$3,000=\$5,750.. Thus, option 5 is the correct choice.
8 0
3 months ago
Read 2 more answers
If you ask three strangers about their birthdays, what is the probability:
Inessa [12570]
Part A:

The probability that all three strangers have their birthdays on a Wednesday is calculated as

\left( \frac{1}{7} \right)^3= \bold{\frac{1}{343}}



Part B:

The probability that the birthdays of the three individuals fall on distinct days throughout the week is calculated as

\left( \frac{1}{7} \right)\left( \frac{1}{6} \right)\left( \frac{1}{5} \right)= \bold{\frac{1}{210}}



Part C:

The probability that none of the three have their birthdays on a Saturday is determined by

\left( \frac{6}{7} \right)^3= \bold{\frac{216}{343}}
8 0
2 months ago
56. Mikayla is filling a glass sphere with water.
Inessa [12570]

Answer:

The least quantity of water needed to fill the sphere is 904.32\ in^{3}

Step-by-step explanation:

We know that

The volume of the sphere (the glass sphere) can be defined as

V=\frac{4}{3}\pi r^{3}

We have

r=12/2=6\ in ----> the radius equals half the diameter

Let’s assume

\pi =3.14

Now substitute

V=\frac{4}{3}(3.14)(6)^{3}

V=904.32\ in^{3}

8 0
3 months ago
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