Three out of twenty toothbrushes are defective, indicating an initial probability of picking one that is defective on the first attempt is 3/20. On the second attempt, because one defective toothbrush has already been removed, the remaining defective ones are 2 out of 19. To find the likelihood of both selections being defective, we multiply the two probabilities. Thus, (3/20)*(2/19) = 6/380, which simplifies to approximately 0.0157, or around 1.6%.
To determine the inverse of f(x)=2x+5, first express it without using f(x). Set y = 2x + 5, then exchange x and y and solve for y. Subtract 5 from both sides to get x - 5 = 2y, and divide through by 2 to find y = (x-5)/2. Therefore, f-1(x) is (x-5)/2. To find f-1(8), substitute 8 for x, resulting in (8-5)/2 = 3/2.
The maximum allowable length related to x is: The peak packaging expense is: The reasonable domain and range values for this function are as follows:
The system of equations to consider would include: p + m = 19 and 0.25p + 0.75m = 11.50. To establish this system, first define the total amount bought with the initial equation where p signifies pens and m denotes markers. The subsequent equation will utilize cost alongside the total expenditure.
Response:
$14
Step-by-step explanation:
35 divided by 20 equals 1.75
8 multiplied by 1.75 results in 14
