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aivan3
17 days ago
12

Using the quadratic formula to solve 2x2 = 4x – 7, what are the values of x? 2 plus-or-minus StartRoot 10 EndRoot i 1 plus-or-mi

nus StartRoot 10 EndRoot i StartFraction 2 plus-or-minus StartRoot 10 EndRoot i Over 2 EndFraction 1 plus-or-minus StartRoot 5 EndRoot i

Mathematics
2 answers:
Zina [9.1K]17 days ago
8 0

Answer:

C. (Refer to the attached image)

Step-by-step explanation:

I’m not inclined to go into detail, but here’s a quick overview:

- subtract -2x^2 from both sides

- input the respective values into their appropriate positions

(Look up the quadratic formula if necessary)

- compute the answer

This response comes from the quadratic Formula enthusiasts, as factoring is seen as outdated.

AnnZ [9K]17 days ago
7 0

Answer:

x = 1 +/- \frac{i\sqrt{10} }{2}

Step-by-step explanation:

The equation provided is:

2x^2 = 4x - 7\\\\2x^2 - 4x + 7 = 0

Applying the quadratic formula:

x = \frac{-b +/- \sqrt{b^2 - 4ac} }{2a}

Based on the details given:

a = 2, b = -4, c = 7

Consequently:

x = \frac{4 +/- \sqrt{(-4)^2 - 4 * 2 * 7} }{2 * 2}\\\\x = \frac{4 +/- \sqrt{(16 - 56)} }{4}\\\\x = \frac{4 +/- \sqrt{-40} }{4}\\

=> x = 1 +/- \frac{i\sqrt{10} }{2}

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Terrence walks at a pace of 2 mi/h to the theater and watches a movie for 2 hours and 15 min he rides a bus back home at 40 mi/h
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Solution:

Let x be the distance in miles from the house to the theater.

Total time taken for the trip =3.5-2.25=1.25 Hr

Then average speed =\frac{Distance}{Time}= \frac{2x}{1.25}\\

Terrence walks at a speed of 2 miles per hour to the theater and returns home at 40 miles per hour.

Thus, Average Speed =\frac{2+40}{2}= 21\\ mi/hr

Both average speeds must be equivalent. Hence, we can express this as:

\frac{2x}{1.25}=21\\
\\
2x=1.25*21\\
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x=13.125\\

Consequently, the distance from home is 13.125 miles.

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27 days ago
The owner of a sandwich shop researches the cost of buying different numbers of pounds of sandwich meat. The owner creates a sca
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Answer:

What are the statements?

Step-by-step explanation:

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8 days ago
The owner of a skate shop notices that every time a certain employee has a shift, there are higher sales numbers at the end of t
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Response:

Correlation.

In-depth explanation:

When the goal is to determine the connection between two or more variables to assess the impact of one variable (the independent one) on another variable (the dependent one), this is referred to as a correlation study or analysis. In this case, the link between employee shifts and sales or productivity is analyzed; it shows how the number of shifts worked by a specific employee correlates positively with the revenue generated. Here, the shift worked by the employee acts as the independent variable while the generated revenue is the dependent one.

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I WILL AWARD BRAINLIEST!! PLEASE HELP!!! The figure below shows the movement of a pedestrian from point B to point E. Using the
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A) The speed of pedestrian BC is 5 km/h

    The speed of pedestrian CD is 0 km/h

    The speed of pedestrian DE is 5 km/h

B) He reached E since the stop after 6 hours

C) The formula for section BC is d(t) = 40 - 5t

    The formula for section CD is d(t) = 20

    The formula for section DE is d(t) = 50 - 5t

Step-by-step breakdown:

A)

In the time-distance graph, speed represents the change in distance with respect to time

this means speed = Δd/Δt ⇒ (slope of the line)

For line BC:

1. Δd = 40 - 20 = 20 km

2. Δt = 4 - 0 = 4 hours

3. The speed = 20 ÷ 4 = 5 km/h

The speed of pedestrian BC stands at 5 km/h

For line CD:

1. Δd = 20 - 20 = 0 km

2. Δt = 6 - 4 = 2 hours

3. The speed = 0 ÷ 2 = 0 km/h

The speed of pedestrian CD is 0 km/h

For line DE:

1. Δd = 20 - 0 = 20 km

2. Δt = 10 - 6 = 4 hours

3. The speed = 20 ÷ 4 = 5 km/h

The speed for pedestrian DE is 5 km/h

B)

∵ He stopped at t = 4 hours

∵ He reached point E at t = 10 hours

∵ 10 - 4 = 6 hours

He arrived at E since the stop took 6 hours

C)

<pthe line="" equations="" are="" characterized="" by:=""><pthe general="" form="" of="" a="" line="" equation="" is="" f="" mx="" c="" where="" m="" represents=""><pthe slope="" and="" c="" is="" the="" y-intercept="" value="" of="" y="" when="" x="" equals="">

1. f(x) is referenced as d(t)

2. m is the speed

3. x corresponds to t

4. You can calculate c by substituting any coordinates of a point along the line into the formula

<pline bc="">

Line BC has a negative slope because d decreases as t increases

∵ m = -5 and c = 40

Thus, d(t) = 40 - 5t

The equation for section BC is d(t) = 40 - 5t

Line CD

Line CD is a horizontal line (which follows the form of any horizontal line represented as y = c)

Thus, m = 0 and c = 20

Therefore, d(t) = 20

The equation for section CD is d(t) = 20

Line DE

Line DE features a negative slope as d decreases along with an increase in t

∵ m = -5

Thus, d(t) = -5t + c

The value of c can be determined by substituting point D's coordinates into the equation

∵ D's coordinates are (6, 20)

Thus, 20 = -5(6) + c

So, 20 = -30 + c

Adding 30 to both sides yields

∴ c = 50

Thus, d(t) = 50 - 5t

The equation for section DE is d(t) = 50 - 5t

Further Learning:

<padditional information="" regarding="" distance="" speed="" and="" time="" can="" be="" found="" in="">

</padditional></pline></pthe></pthe></pthe>
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