Using the quadratic formula to solve 2x2 = 4x – 7, what are the values of x? 2 plus-or-minus StartRoot 10 EndRoot i 1 plus-or-mi

Question

2 months ago

12

nus StartRoot 10 EndRoot i StartFraction 2 plus-or-minus StartRoot 10 EndRoot i Over 2 EndFraction 1 plus-or-minus StartRoot 5 EndRoot i

2 answers:

Zina [12.3K] · Answer 1 · 2026-03-10T18:20:41+03:00

Answer:

C. (Refer to the attached image)

Step-by-step explanation:

I’m not inclined to go into detail, but here’s a quick overview:

- subtract -2x^2 from both sides

- input the respective values into their appropriate positions

(Look up the quadratic formula if necessary)

- compute the answer

This response comes from the quadratic Formula enthusiasts, as factoring is seen as outdated.

AnnZ [12.3K] · Answer 2 · 2026-03-10T18:20:16+03:00

7 0

Answer:

$x = 1 +/- \frac{i\sqrt{10} }{2}$

Step-by-step explanation:

The equation provided is:

$2x^2 = 4x - 7\\\\2x^2 - 4x + 7 = 0$

Applying the quadratic formula:

$x = \frac{-b +/- \sqrt{b^2 - 4ac} }{2a}$

Based on the details given:

a = 2, b = -4, c = 7

Consequently:

$x = \frac{4 +/- \sqrt{(-4)^2 - 4 * 2 * 7} }{2 * 2}\\\\x = \frac{4 +/- \sqrt{(16 - 56)} }{4}\\\\x = \frac{4 +/- \sqrt{-40} }{4}\\$

=> $x = 1 +/- \frac{i\sqrt{10} }{2}$