The three equivalent numerical expressions are:
Solutions to create three numerical expressions equivalent to (0.0004). (0.005)
The conversion between these units is 1 km/hr = 0.62 m/hr
The result is 10/117. We have three distinct letters and four unique non-zero digits. For letters, we have 26 options from A to Z. For digits, there are 9 choices from 1 to 9. As all selections must be distinct, we find the total number of codes as 26 × 25 × 24 × 9 × 8 × 7 × 6. For the specified code, we focus on the combinations with 5 vowels and 4 even digits, leading to a calculation of 5 × 25 × 24 × 8 × 7 × 6 × 4. Probability can thus be expressed as the ratio of these outcomes, yielding: 5 × 25 × 24 × 8 × 7 × 6 × 4 divided by 26 × 25 × 24 × 9 × 8 × 7 × 6.
Answer:
Step-by-step explanation:
Considering the equation
Sin(5x) = ½
5x = arcSin(½)
5x = 30°
Then,
The general formula for sin is
5θ = n180 + (-1)ⁿθ
Dividing throughout by 5
θ = n•36 + (-1)ⁿ30/5
θ = 36n + (-1)ⁿ6
The solution range is
0<θ<2π which means 0<θ<360
First solution
When n = 0
θ = 36n + (-1)ⁿθ
θ = 0×36 + (-1)^0×6
θ = 6°
When n = 1
θ = 36n + (-1)ⁿ6
θ = 36-6
θ = 30°
When n = 2
θ = 36n + (-1)ⁿ6
θ = 36×2 + 6
θ = 78°
When n =3
θ = 36n + (-1)ⁿ6
θ = 36×3 - 6
θ = 102°
When n=4
θ = 36n + (-1)ⁿ6
θ = 36×4 + 6
θ = 150
When n=5
θ = 36n + (-1)ⁿ6
θ = 36×5 - 6
θ = 174°
When n = 6
θ = 36n+ (-1)ⁿ6
θ = 36×6 + 6
θ = 222°
When n = 7
θ = 36n + (-1)ⁿ6
θ = 36×7 - 6
θ = 246°
When n =8
θ = 36n + (-1)ⁿ6
θ = 36×8 + 6
θ = 294°
When n =9
θ = 36n + (-1)ⁿ6
θ = 36×9 - 6
θ = 318°
When n =10
θ = 36n + (-1)ⁿ6
θ = 36×10 + 6
θ = 366°
When n = 10 surpasses the θ range
Thus, the solutions range from n =0 to n=9
Therefore, there are 10 solutions within the interval 0<θ<2π
The equation for the problem is 
≤ 
Hope this is useful!
