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notka56
2 months ago
15

The weight, w, in tons of a school bus is related linearly to its seating capacity, p. a 60-passenger bus weighs 10 tons, and an

84-passenger school bus weighs 13 tons. which equation can be used to find the weight of a 50-passenger bus?

Mathematics
2 answers:
lawyer [12.5K]2 months ago
7 0
A linear equation representing the relationship between two entities can be expressed as:
                                    y = ax + b
Here, x denotes the number of passengers while y represents the weight (in tons). Based on the initial two scenarios,
                                    10 = 60(a) + b
                                     13 = 84(a) + b
The calculated values for a and b are 0.125 and 2.5 respectively.
For a bus designed for 50 passengers,
                                    y = (50)(0.125) + 2.5
This results in y being equal to 8.75. 
lawyer [12.5K]2 months ago
3 0

The correct option is D!

w - 10 = 1/8(50 - 60)

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a pet store owner set the price of a bag of cat food at 50% above the cost. when it did not sell, the price was reduced 20% to 1
babunello [11817]

Answer:

The original cost amounts to $10

Step-by-step explanation:

Let us denote the cost as x

where Price = x + (0.5x) = 1.50x

Now, the price after reduction is 20% of 1.50x

which is 0.3x \frac{20}{100}

This leads to the equation 1.50x - 0.3x = 12

resulting in 1.2x = 12

which gives us x = 10

\frac{12}{1.2}thus, the cost is $10

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1 month ago
A sequence is defined by mc024-1.jpg, and mc024-2.jpg. What is the seventh term?
AnnZ [12381]
Given data:
a₃ = 9/16
aₓ = -3/4 · aₓ₋₁
Here, x represents the number of terms ('x' can also be referred to as 'n')
To determine the 7th term (a₇):

We know that aₓ = -3/4 · aₓ₋₁
Thus,[ [TAG_10]]a₃ = -3/4 · a₃₋₁
a₃ = -3/4 · a₂
9/16 = -3/4 · a₂
a₂ = 9/16 × -4/3
a₂ = -36/48
a₂ = -3/4

Next,[ [TAG_20]]aₓ = -3/4 · aₓ₋₁
a₄ = -3/4 · a₄₋₁
a₄ = -3/4 · a₃
a₄ = -3/4 · 9/16
a₄ = -27/64
a₄ = -27/64

For a₅,[ [TAG_30]]aₓ = -3/4 · aₓ₋₁
a₅ = -3/4 · a₅₋₁
a₅ = -3/4 · a₄
a₅ = -3/4 × -27/64
a₅ = 81/256

For a₆,[ [TAG_39]]aₓ = -3/4 · aₓ₋₁
a₆ = -3/4 · a₆₋₁
a₆ = -3/4 · a₅
a₆ = -3/4 × 81/256
a₆ = -243/1024

Finally, for a₇,[ [TAG_48]]aₓ = -3/4 · aₓ₋₁
a₇ = -3/4 · a₇₋₁
a₇ = -3/4 · a₆
a₇ = -3/4 × -243/1024
a₇ = 729/4096
3 0
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