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1 month ago

14

If two different people are randomly selected from the 884 subjects, find the probability that they are both women. Round to fou

r decimal places.

1 answer:

zzz [12.3K]1 month ago

5 0

The result is 0.3274

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For the month of June, Mae Green budgeted the following amounts: $180 for food, $475 for rent, $15 for transportation, $50 for i

tester [12383]

Question 1

Total budget sums up to 180 + 475 + 15 + 50 + 65 + 25 + 150 + 30 = $990.
Actual expenditure amounts to 182 + 475 + 12 + 65 + 68 + 12.50 + 150 + 36 = $1000.5.

Mae Green surpassed her designated budget.

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Question 2

Eleanor:
Earned = 380.48
Spent = 16.50

Peter:
Earned = 120 + 13.65 + 100 = 233.65.

Combined total income = 233.65 + 380.48 - 16.50 = 597.63.

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Question 3

Aggregate expenditure = 540 + 48.55 + 34.15 + 12.80 + 18.95 + 38.60 + 2 + 6.50 = 701.55.

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Question 4

Marie's updated balance = 250.65 - [21.95+48.50+75.60] + 55 = $159.50.

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Question 5

[235/825] × 100 = 28.48%

4 1

2 months ago

Read 2 more answers

What is the logarithm of the equilibrium constant, log K, at 25°C of the voltaic cell constructed from the following two half-re

lawyer [12517]

Answer:

4.0921 reflects the logarithm of the equilibrium constant.

Step-by-step explanation:

$Fe^{2+} (aq) +2e^{-}\rightarrow Fe(s)$ ; E° = - 0.41 V

$Ag^+(aq) + e^-\rightarrow Ag(s)$ ; E° = 0.80 V

Iron has a negative reduction potential, indicating its tendency to lose electrons and undergo oxidation, and thus it will be at the anode.

$E^{o}_{cell}$ =Reduction potential of cathode - Reduction potential of anode

$E^{o}_{cell}=E^{o}_c-E^{o}_a$

$=0.80 V-(-0.41 V)=1.21 V$

$Fe^{2+} (aq) + 2e^{-}\rightarrow Fe(s)$ ; E° = - 0.41 V

$2Ag^+(aq) + 2e^-\rightarrow 2Ag(s)$ ; E° = 0.80 V

Net reaction: $Fe(s)+2Ag^{+}\rightarrow Fe^{2+}+2Ag(s)$

n = 2

To determine the equilibrium constant, we utilize the correlation with Gibbs free energy, as follows:

$\Delta G^o=-nfE^o_{cell}$

and,

$\Delta G^o=-RT\ln K_{eq}$

Aligning these two equations yields:

$nfE^o_{cell}=RT\ln K_{eq}$

where,

n = electrons transferred = 2

F = Faraday's constant = 96500 C

$E^o_{cell}$ = standard electrode potential of the cell = 1.21 V

R = gas constant = 8.314 J/K.mol

T = reaction temperature = $25^oC=[273+25]=298K$

Substituting values into the equation, we arrive at:

$2\times 96500\times 1.21 V=8.314\times 298\times \ln K_{eq}$

$\ln K_{eq}=9.3478$

$\log K_{eq}=\frac{9.3478}{2.303}=4.0921$

4.0921 represents the logarithm of the equilibrium constant.

7 0

2 months ago

Kari would like to save $10,000 for a down payment on a house illustrate the difference in years it will take her to double her

Leona [12618]

6%=5,300 12%=5,600 18%=5,900 That summarizes my full response based on the provided details.

5 0

1 month ago