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Stels
14 days ago
7

The value of a car t years after it is purchased is given by the decreasing function V, where V(t) is measured in dollars. The r

ate of change of the car’s value in dollars per year is proportional to the car’s value. Which of the following differential equations could be used to model the value of the car, where k is a constant?
Mathematics
1 answer:
PIT_PIT [3.9K]14 days ago
7 0

Answer:

dV(t)/dt = kV(t)

Step-by-step explanation:

The annual change in the car's value, represented by dV(t)/dt, has a proportional relationship with V(t), the car's current value.

dV(t)/dt ∝ V(t)

dV(t)/dt = kV(t)

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Find the distance across the lake. Assume the triangles are similar.
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Response:

B. 255 m

Detailed breakdown:

utilize similar triangles

L / 60 = 85 / 20

L = (85 * 60) / 20

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13 days ago
A rectangular schoolyard is to be fenced in using the wall of the school for one side and 150
lawyer [4039]

Answer:

Part 1) The equation is A(x)=150x-2x^2

Part 2) When x=40 m, the area of the schoolyard is A=2,800 m^2

Part 3) The valid domain consists of all real numbers exceeding zero and below 75 meters

Step-by-step explanation:

Part 1) Formulate an expression for A(x)

Let

x -----> the length of the rectangular school yard

y ---> the width of the rectangular school yard

It is known that

The perimeter for the fencing (taking the school wall as one side) is

P=2x+y

P=150\ m

thus

150=2x+y

y=150-2x -----> this is equation A

The area of the rectangular school yard is

A=xy ----> this is equation B

Substituting equation A into equation B yields

A=x(150-2x)

A=150x-2x^2

Change to function notation

A(x)=150x-2x^2

Part 2) What is the area when x=40?

With x equal to 40 m

substitute the value into the expression from Part 1 to determine A

A(40)=150(40)-2(40^2)

A(40)=2,800\ m^2    

Part 3) What would be a suitable domain for A(x) in this scenario?

We understand that

A signifies the area of the rectangular school yard

x characterizes the length of the rectangular school yard

It follows that

A(x)=150x-2x^2

This forms a vertical parabola opening downwards

The vertex indicates a maximum point

The x-coordinate of the vertex corresponds to the length that maximizes the area

The y-coordinate of the vertex denotes the maximum area

The vertex corresponds to (37.5, 2812.5)

Refer to the accompanying figure

Consequently,

The peak area achieved is 2,812.5 m^2

The x-intercepts are located at x=0 m and x=75 m

The domain for A is the range -----> (0, 75)

All real numbers greater than zero and less than 75 meters

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11 days ago
if a student scored 78 points on a test where the mean score was 84.5 and the standard deviation was 3.1. the student's z score
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Answer:

(value - mean)/standard deviation.

Now substitute 78 for the value, 84.5 for the mean, and 3.1 for the standard deviation.

Step-by-step explanation:

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3 days ago
How do you solve m=10x-x for x
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<span>m=10x-x for x
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12 days ago
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Answer:

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Step-by-step explanation:

Stated as follows:

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Now, according to the problem:

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Consequently, Ф = \frac{38 feet}{18 feet}

Therefore, Ф = 2.11 °

Thus, the rotation angle is Ф = 2.11 °

Hence, the rotation angle is 2.11 ° Answer

6 0
16 days ago
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