Given the specified angles, one is 90 degrees, indicating that the triangle is a right triangle. With provided angles and one side representing the hypotenuse (the longest side), the area is determined using the formula: Area = 1/2 * base * height. Let's compute the height and base:
From sin 75, we derive height = 1.67.
And from cos 75, we obtain base = 0.45.
Calculating area gives us Area = (0.45 * 1.67) / 2, resulting in 0.37 square units.
Thus, the triangle's area is approximately 0.37 square units.
Answer:
2.55 cubic meters of sand
Step-by-step explanation:
The inquiry focuses on how much sand is needed to completely fill the sandbox. As it is a three-dimensional shape, the concept of 'Volume' is applicable. Volume is determined through the formula L × W × H. By substituting the relevant variables into this equation, you arrive at the final solution. I hope this offers clarity!
They cannot possess the same number of horses; let me clarify. If you divide 21 horses among four individuals, you would perform 21/4, yielding 5.25, implying that fractional horses are unfeasible. Therefore, at least one individual must have 6 horses instead of 5. Possibly, this is what your instructor wants you to understand. For an even distribution, they could sell one horse, making it 20, so each would then have 5 horses. Alternatively, they might share the extra horse to rotate its usage.
Let’s consider the curve: r(t) = t²i +(int)j + 1/t k
X = t², y = int,z = 1/t
Utilizing x = t² and z = 1/t
X = (1/z)²
Xz² = 1
Now using y = int and z= 1/t
Y = in│1/z│
By using x = t² and y = int
Y = int = in(√x)
Thus, the resulting surfaces are,
Xz² = 1
Y = in│1/z│
Y= in(√x)
A normal distribution is most effective when dealing with a substantial sample size. Without knowing how many containers there are, it's challenging to determine if it’s suitable for modeling the container weights.
