adam and betty purchased a printer together for $258. If adam paid $18 less than twice betty, how much money did Adam pay for th

Her phrasing suggests that she would sell numerous water bottles and just a single iced tea. The accurate equation should be 1.25x + 1.49y = 100, as she may offer varying quantities of both.

Answer:

Step-by-step explanation:

Considering the equation

Sin(5x) = ½

5x = arcSin(½)

5x = 30°

Then,

The general formula for sin is

5θ = n180 + (-1)ⁿθ

Dividing throughout by 5

θ = n•36 + (-1)ⁿ30/5

θ = 36n + (-1)ⁿ6

The solution range is

0<θ<2π which means 0<θ<360

First solution

When n = 0

θ = 36n + (-1)ⁿθ

θ = 0×36 + (-1)^0×6

θ = 6°

When n = 1

θ = 36n + (-1)ⁿ6

θ = 36-6

θ = 30°

When n = 2

θ = 36n + (-1)ⁿ6

θ = 36×2 + 6

θ = 78°

When n =3

θ = 36n + (-1)ⁿ6

θ = 36×3 - 6

θ = 102°

When n=4

θ = 36n + (-1)ⁿ6

θ = 36×4 + 6

θ = 150

When n=5

θ = 36n + (-1)ⁿ6

θ = 36×5 - 6

θ = 174°

When n = 6

θ = 36n+ (-1)ⁿ6

θ = 36×6 + 6

θ = 222°

When n = 7

θ = 36n + (-1)ⁿ6

θ = 36×7 - 6

θ = 246°

When n =8

θ = 36n + (-1)ⁿ6

θ = 36×8 + 6

θ = 294°

When n =9

θ = 36n + (-1)ⁿ6

θ = 36×9 - 6

θ = 318°

When n =10

θ = 36n + (-1)ⁿ6

θ = 36×10 + 6

θ = 366°

When n = 10 surpasses the θ range

Thus, the solutions range from n =0 to n=9

Therefore, there are 10 solutions within the interval 0<θ<2π

Purchasing the first 10 bricks at $4.50 each totals $45. The subsequent 10 bricks at $3.50 each add $35. This uses $80, leaving $20 to buy bricks priced at $2.50 each, allowing for 8 more bricks. Altogether, $100 can buy 28 bricks.

<span>The accurate answer is "<span>The experimental probability is 1/15 lower than the theoretical probability."

The attached table illustrated in the image indicates that the theoretical probabilities are: 2/5 for drawing a Jack, 4/15 for a Queen, and 1/3 for a King, based on the frequency of each card in the set.
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Answer:

The polynomial expression

To ascertain the multiplicity of 0, -2, -4, 5.

The multiplicity refers to how many times a root appears in a function.

First, identify the function's roots by setting it to zero.

Thus, the roots are x=0, -2, -4, and 5

To determine the roots' multiplicities:

The factor of x will give a root of x=0 with a multiplicity of 1

likewise,  x=-2 with a multiplicity of 3

x=-4 with a multiplicity of 2

and x=5 with a multiplicity of 4.