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13 days ago

Share 747 pounds in the ratio 2:7 between tom and ben

2 answers:

8 0

To divide 747 pounds between Tom and Ben according to the ratio of 2:7, you need to split 747 by 2+7=9 to find out the weight for one part of the 9 total parts.

747:9=83.

Tom should receive 2 parts, which equates to 83·2=166 pounds, while Ben should receive 7 parts, which totals 83·7=581 pounds.

Result: you should distribute 166 pounds to Tom and 581 pounds to Ben.

Svet_ta [9.5K]13 days ago

6 0

2x+7x=747
9x=747
x=83

83(2) = 166
83(7) = 581

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In a spelling bee, scholarships are awarded to the top three spellers. The first-place speller receives $5,000. The second-place

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21 day ago

Use this information to find the value of b. c = 25 s = 9 b = 4c - s2

PIT_PIT [9117]

Greetings!

Let's rewrite the equation:
b = 4c - s².
Plug in your values:
b = 4(25) - (9)²
Now simplify:
4 times 25 equals 100
9 squared equals 81
So, b = 100 - 81
Calculate:
100 minus 81 equals 19
b is 19.

I hope this helps!
Best of luck:) 

- Hannah ❤

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25 days ago

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a) $P(X>20)=P(\frac{X-\mu}{\sigma}>\frac{20-\mu}{\sigma})=P(Z>\frac{20-15}{3.5})=P(z>1.43)$

The probability can be determined using the complement rule, with the standard normal distribution, an excel sheet, or a calculator.

$P(z>1.43)=1-P(z$

b) $P(X$

This probability can also be calculated using the normal standard distribution, an excel sheet, or a calculator.

$P(z$

c) $P($

For this one, the probability can likewise be derived from the standard normal distribution, excel, or a calculator, with specific adjustments:

$P(-1.43$

Step-by-step explanation:

Previous concepts

Normal distribution refers to a symmetric probability distribution centered around the mean, indicating that occurrences near the mean are more common than those far from it.

The Z-score is a statistic that represents a value's relationship to the average of a set of values, expressed in terms of how many standard deviations it is away from the mean.

Part a

Let X denote the random variable representing the lengths within a population, and for our case, the distribution for X is as follows:

$X \sim N(15,3.5)$

Where $\mu=15$ and $\sigma=3.5$

We seek the probability:

$P(X>20)$

The most effective way to solve this is by leveraging the normal distribution and the corresponding Z-score:

$z=\frac{x-\mu}{\sigma}$

By applying this formula, we can find the probability:

$P(X>20)=P(\frac{X-\mu}{\sigma}>\frac{20-\mu}{\sigma})=P(Z>\frac{20-15}{3.5})=P(z>1.43)$

Again, this probability can be obtained either using the complement rule, the standard normal distribution, or a calculator.

$P(z>1.43)=1-P(z$

Part b

$P(X$

This probability can also be computed using either the normal standard distribution, an excel sheet, or a calculator.

$P(z$

Part c

$P($

In this case, the probability can similarly be acquired with the help of the standard normal distribution, an excel sheet, or a calculator, with particular adjustments:

$P(-1.43$

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The result I obtained is 937.5.

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