The distance from the bottom of the wheel to a point on the ground can be expressed using the sine function h(t) = a*sin(kt) + b, where b represents the height of the wheel at 4m. The radius a is calculated as 50/2 = 25m. Since it takes 6 minutes for 3 complete rotations, the period can be derived from 2π/k, giving us k = π. Thus, h(t) = 25*sin(π*t) + 4.
Your total time will be 2 hours and 10 minutes.
Answer:
mCEA = 90ᴼ, as CEA forms a right angle, and by definition, right angles measure 90ᴼ.
The angle CEF is classified as a straight angle as it combines two right angles (CEA and AEF), equating to 180ᴼ altogether. Straight lines are defined to measure 180ᴼ.
AEF is determined to be a right angle as CEA is already a right angle, and since CEF is a straight line, AEF must also be a right angle.
Initially, we convert the given radius of the wheel into meters, resulting in 0.325 m. Next, we compute the circumference.
C = 2πrr
By inserting the values,
C = 2π(0.325 m) = 2.04 m
Given a distance of 40 m for the road, we calculate the total number of complete revolutions as follows:
n = 40/2.04 m = 20.
