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Romashka
2 months ago
11

The International Business Club starts the school year with $250.50 in their account. They spend $35 each month on activities. T

he Future Agricultural Leaders Club starts with $300 and spends $45.25 each month. Which equation can be used to find m, the number of months it will take for both accounts to have the same amount of money? 250.5 + 35m = 300 + 45.25m 250.5 – 35m = 300 – 45.25m 250.5m – 35 = 300m – 45.25 250.5m + 35 = 300m + 45.25
Mathematics
1 answer:
Zina [12.3K]2 months ago
7 0

Answer:

250.50 - 35m = 300 - 45.25m

Step-by-step explanation:

In instances where an equation explores when an amount x (or m in this case) will occur, it's essential to know that two separate equations need to match each other

The equation established will be 250.50 - 35m = 300 - 45.25m

The term 35m is deducted from 250.50 because money is being lost each time it is spent. The same applies to 45.25m

Furthermore, both 35m and 45.25m serve as variables due to the indication of monthly expenses without a specified duration, necessitating the inclusion of a variable behind it.

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Recycled cd’s incorporated, offers a choice of 5 used CD for $24, with each additional CD costing $5. Write a cost function for
AnnZ [12381]

If $24 is the price for the 5 used CDs, then your formula would be "24+5x" where x represents the count of additional CDs you buy.

24+5(6-5)

24+5(1)

24+5

=29


Thus, acquiring 6 CDs would cost $29


I hope that’s accurate, good luck^^

5 0
3 months ago
Jenny multiplies the square root of her favorite positive integer by $\sqrt{2}$. Her product is an integer. a) Name three number
tester [12383]

Answer:Part a) 2,50,18

Part b) When Jenny divides the square root of her favorite positive integer by \sqrt{2}, the result is an integer.

Step-by-step explanation:

Let

x-------> the favorite positive integer

Part a)

1) For x=2

\sqrt{2}*\sqrt{2}=\sqrt{4}=2 -----> the product results in an integer

thus

The number x=2could potentially be Jenny's favorite positive integer

2) For x=50

\sqrt{50}*\sqrt{2}=\sqrt{100}=10 -----> the product results in an integer

thus

The number x=50could potentially be Jenny's favorite positive integer

3) For x=18

\sqrt{18}*\sqrt{2}=\sqrt{36}=6 -----> the product results in an integer

thus

The number x=18could potentially be Jenny's favorite positive integer

Part B)

1) For x=2

\sqrt{2}/\sqrt{2}=\sqrt{1}=1 -----> the outcome is an integer

2) For x=50

\sqrt{50}/\sqrt{2}=\sqrt{25}=5 -----> the outcome is an integer

3) For x=18

\sqrt{18}/\sqrt{2}=\sqrt{9}=3 -----> the outcome is an integer

Therefore

When Jenny divides the square root of her favorite positive integer by \sqrt{2}, she obtains an integer as a result.

4 0
1 month ago
Malik randomly picked two numbers from 1 to 9 (Includin 1 and 9). the same number could be picked more than once. The first of t
tester [12383]

Response:

2/9 = 0.22

Clarification:

There are two ways to select the first number that is odd and less than 5: 1 and 3.

For each of these, the second number drawn can be any of the values from 1 to 9, giving us a total of 18 options.

Out of these, the only pairs that result in a sum less than 5 are (1,1), (1,2), (1,3), and (3,1). Thus we have 4 combinations from the total of 18:

4/18 = 2/9 = 0.22

8 0
2 months ago
iven: C is a point on the perpendicular bisector, l, of AB. Prove: AC = BC Use the drop-down menus to complete the proof. By the
Leona [12618]

Answer:

For a clearer understanding, refer to the attached figure:

Step-by-step breakdown:

1. According to the unique line postulate, only one line segment can be created: BC

This is because a single line can only connect two distinct points.

2. Utilizing the definition of reflection, reflect BC across l.

To identify the line segment reflected over l, we will apply the reflection definition.

3. Based on the reflection definition, C remains as its own image and A represents the image of B.

The reflection definition states that a figure is transformed into a mirror image around a line. Thus, CD serves as the perpendicular bisector of AB, which makes A and B equidistant from D, producing their mirror images.

4. Because reflections maintain length, we find that AC = BC

In a reflection, the figure transforms to create a mirror image, ensuring the lengths remain unchanged.

8 0
2 months ago
Read 2 more answers
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