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dangina
2 months ago
11

The completed construction of a regular hexagon is shown below. Explain why ACF is a 30º-60º-90º triangle.

Mathematics
1 answer:
PIT_PIT [12.4K]2 months ago
5 0

A typical regular hexagon consists of six equilateral triangles.

One of these is ΔAFM, where each angle measures 60°, so ∡AFM = 60°.

ΔABC is classified as an isosceles triangle, possessing an angle of ∡ABC = 120°, as each internal angle in a regular hexagon measures 120°.

Angles ∡BAC and ∡BCA each equal 30°, summing to 180° in total for the triangle.

Moreover, ∡ACF is congruent to ∡BCA = 30°. Therefore, we can deduce that angle ∡FAC equals 90°. The reasoning for this follows.

Best of luck!!!

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