Work out ( 8x10 -3) x(2x10 -4) standard form

Yao Xin puts 3/10 liters of potting soil in each pot for planting flowers. She has 17/3 liters of potting soil. How many pots ca

babunello [8423]

In this scenario, we'll define the following variables:

x: total volume of potting soil in liters.

y: quantity of potting soil allocated to each pot in liters.

To determine the number of pots, we can use the expression:

$N = \frac{x}{y}$

Substituting in the respective values yields:

$N = \frac{\frac{17}{3}}{\frac{3}{10}}$

Reformatting gives us:

$N = \frac{170}{9}$

$N = 18.8$

When rounding down to the nearest whole number, we find:

$N = 18$

The conclusion is:

Yao Xin is capable of filling 18 pots.

4 0

12 days ago

Suppose you have two urns with poker chips in them. Urn I contains two red chips and four white chips. Urn II contains three red

Zina [9179]

There are several possible outcomes. The initial composition of the urns is as follows: Urn 1 contains 2 red chips and 4 white chips, totaling 6 chips, whereas Urn 2 has 3 red and 1 white, amounting to 4 chips. When a chip is drawn from the first urn, the probabilities are as follows: for a red chip, it is probability is (2 red from 6 chips = 2/6 = 1/2); for a white chip, it is (4 white from 6 chips = 4/6 = 2/3). After the chip is transferred to the second urn, two scenarios can arise: if the chip drawn from the first urn is white, then Urn 2 will contain 3 red and 2 white chips, making a total of 5 chips, creating a 40% chance for drawing a white chip. Conversely, if a red chip is drawn first, Urn 2 will contain 4 red and 1 white chip, which results in a 20% chance of drawing a white chip. This scenario exemplifies a dependent event, as the outcome hinges on the type of chip drawn first from Urn 1. For the first scenario, the combined probability is (the probability of drawing a white chip from Urn 1) multiplied by (the probability of drawing a white chip from Urn 2), equaling 26.66%. For the second scenario, the probabilities yield a value of 6%.

8 0

12 days ago

Axline Computers manufactures personal computers at two plants, one in Texas and the other in Hawaii. The Texas plant has 40 emp

Zina [9179]

Answer:

a) The likelihood that none of the sampled employees are from the Hawaii plant is 1.74%.

b) The chance that exactly 1 employee from the sample is found working in the Hawaii plant is 8.70%.

c) There is an 89.56% chance that 2 or more employees in the sample are from the Hawaii plant.

d) The probability that 9 employees from the sample are working at the Texas plant is 8.70%.

Step-by-step explanation:

Each employee has two potential employment locations: either Texas or Hawaii. Thus, the binomial probability distribution can be utilized to solve this scenario.

Binomial probability distribution

This distribution defines the probability of achieving exactly x successes in n trials where there are only two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

Here, $C_{n,x}$ denotes the number of ways to choose x objects from a set of n, represented by the subsequent formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of success occurring.

In this context, we know:

The sample comprises 10 employees, therefore $n = 10$ .

a. Calculate the probability that none of the sampled employees are from the Hawaii plant (to 4 decimals)?

Given that 20 out of 60 employees are based in Hawaii:

$p = \frac{20}{60} = 0.333$

We aim to find P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.333)^{0}.(0.667)^{10} = 0.0174$

Thus, the likelihood that none in the sample are from Hawaii stands at 1.74%.

b. Calculate the probability that 1 employee from the sample is from the Hawaii plant?

This is represented as P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{10,1}.(0.333)^{1}.(0.667)^{9} = 0.0870$

Therefore, there is an 8.70% possibility that 1 employee in the sample comes from Hawaii.

c. Calculate the probability that 2 or more employees in the sample are from the Hawaii plant?

We can observe two scenarios: either fewer than 2 employees are from Hawaii or 2 and beyond. The combined probabilities equal decimal 1. So:

$P(X < 2) + P(X \geq 2) = 1$

We seek to find $P(X \geq 2)$ .

$P(X \geq 2) = 1 - P(X < 2)$

From problems a and b, we possess values for both probabilities.

$P(X < 2) = P(X = 0) + P(X = 1) = 0.0174 + 0.0870 = 0.1044$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.1044 = 0.8956$

Accordingly, the chance that 2 or more employees in this sample operate at the Hawaii plant is 89.56%.

d. Calculate the likelihood that 9 employees in the sample are working at the Texas plant?

This corresponds to the probability found in part b for 1 employee working in Hawaii.

Consequently, there is an 8.70% chance that 9 employees belong to the Texas plant.

6 0

22 days ago

Ranger was given this expression to simplify. 4(2x – 5) What advice to simplify the expression would you give Ranger? Check all

Zina [9179]

This situation exemplifies the distributive property, where the number outside the parentheses impacts all the terms within through multiplication. Therefore, the resulting action here is:

<span>The 4 should be multiplied by each term found inside the parentheses.

</span>

5 0

28 days ago

Read 2 more answers

Carmen is going to roll an 8-sided die 200 times. She predicts that she will roll a multiple of 4 twenty-five times. Based on th

AnnZ [9104]

Answer:

Carmen's estimate is too low, since rolling 200 times $\frac{1}{4}$ results in a total of 50.

Step-by-step explanation:

Initially, we will define the sample space for this scenario.

The sample space is Ω = {1,2,3,4,5,6,7,8}

For the event A: "Rolling an 8-sided die to get a multiple of 4"

The probability for event A is $P(A)=\frac{2}{8}=\frac{1}{4}$

This is because there are two multiples of 4 (4 and 8) out of a total of eight numbers (1 through 8).

Next, considering the random variable X: "Total count of multiples of 4 if she rolls an 8-sided die 200 times"

X can be described as following a Binomial distribution.

X ~ Bi (n,p)

X ~ Bi (200, $\frac{1}{4}$ )

Where n is the number of rolls and p is the probability of success, defined as rolling a multiple of 4.

The mean for this variable is

$E(X)=np=200.\frac{1}{4}=50$

Thus, we conclude that Carmen's prediction is low, as rolling 200 times $\frac{1}{4}$ yields 50.

4 0

19 days ago

Read 2 more answers