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tensa zangetsu
17 days ago
15

Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 4 h, and Car B traveled the dista

nce in 4.5 h. Car B traveled 5 mph slower than Car A. (The formula R⋅T=D , where R is the rate of speed, T is the time, and D is the distance can be used.) How fast did Car B travel? Enter your answer in the box.
Mathematics
2 answers:
zzz [9K]17 days ago
8 0
Let x denote the speed of car B, which is 5 mph less than car A's speed. Thus, car A travels at a rate of x + 5 mph. To find the distances, we apply the formula RT = D. Hence, the distance for car A is 4(x + 5) and for car B, it is 4.5x. As both cars covered the same distance, this leads to the equation 4(x + 5) = 4.5x. Rearranging gives us 4x + 20 = 4.5x. This simplifies to 0.5x = 20, resulting in x = 40. Therefore, car B's speed is 40 mph.
Leona [9.2K]17 days ago
5 0

For those who are unable to view the confirmed solution, car B's speed was 40 mph.

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