replace each star with a digit to make the problem true.Is there only one answer to each problem? ****-***=2

Answer:

A. Combining one pound of pistachios with one pound of almonds costs $20.

C. Decreasing the almond quantity by one pound leads to a total price of $40.

E. The price p (in dollars) per pound of pistachios is represented by the equation 2p + 3(p – 4) = 48.

Step-by-step explanation:

Let:

x = cost per pound of pistachios

y = cost per pound of almonds

We know that

x = y + 4 (Equation A)

2x + 3y = 48 (Equation B)

Substitute x from Equation A into Equation B:

2(y + 4) + 3y = 48

2y + 8 + 3y = 48

5y = 48 – 8

y = 8

Find x:

x = 8 + 4 = 12

Therefore, pistachios cost $12 per pound and almonds cost $8 per pound.

Verify the statements:

Case A) One pound of each equals $20.

True, since 12 + 8 = 20.

Case B) Pistachios cost twice as much as almonds.

False, because 2 × 8 = $16 ≠ $12.

Case C) Reducing almond pounds by 1 yields $40 total.

True, as 2(12) + 2(8) = 24 +16 = 40.

Case D) The almond cost modeled by 2(a – 4) + 3a = 48.

False; it should be 2(a + 4) + 3a = 48.

Case E) The pistachio cost modeled by 2p + 3(p – 4) = 48.

True, since p = a + 4 implies a = p – 4.

Response:

Her brother catches up to her at 11 am + 4 hours = 15 p.m

Detailed explanation:

Provided information;

Ariel's speed = 45 mph

She departed at 9 a.m

Her brother's speed = 60 mph

He began at 11 a.m

Inferred from the question: Since Ariel's speed is 45 mph, after two hours she is ahead by 90 miles.

Meanwhile, her brother travels at 60 mph, hence he is traveling (60 - 45) = 15 mph faster

Therefore, with this speed, he will catch up to her in = 4 hours.

So her brother catches up with her at 11 am + 4 hours = 15 p.m

Imagine having a pile of pennies and you want to determine if the count is odd or even without tallying them one by one. You can separate them into pairs by placing one coin in the left pile and one in the right.

If no coin is left unmatched, then the total number is even; if there is one coin remaining unpaired, the number is odd.

The transformation sequence that maps ΔBCD to ΔB"C"D" is:

Reflection across the y-axis combined with a translation of 6 units in the x direction and -5 units in the y direction.

Step-by-step explanation:

Let's break down the reflection across the y-axis, horizontal translation, and vertical translation:

1. For point (x, y), reflecting it across the y-axis gives the point (-x, y).

2. Translating point (x, y) h units to the right results in (x + h, y), and h units to the left results in (x - h, y).

3. If point (x, y) is moved k units up, it becomes (x, y + k), and if moved k units down, it is (x, y - k).

∵ The vertices of triangle BCD are (1, 4), (1, 2), (5, 3).

∵ The vertices of triangle B'C'D' are (-1, 4), (-1, 2), (-5, 3).

∵ The x-coordinates of ΔB'C'D' have the same absolute value as those of ΔBCD but with opposite signs, indicating that ΔB'C'D' results from reflecting ΔBCD across the y-axis.

∵ The vertices of triangle B'C'D' are (-1, 4), (-1, 2), (-5, 3).

∵ The vertices of triangle B''C''D'' are (5, -1), (5, -3), (1, -2).

∵ The reflected x-coordinate -1 becomes +5, and -5 becomes +1,

thus the x-coordinates of triangle B'C'D' are increased by 6.

∵ The images of 4, 2, and 3 yield -1, -3, and -2 respectively,

hence subtracting 5 from the y-coordinates of triangle B'C'D' leads us to ΔB"C"D" through a translation of 6 units right and 5 units down ⇒ (x + 6, y - 5).

The transformation sequence that maps ΔBCD to ΔB"C"D" is:

Reflection across the y-axis combined with a translation of 6 units in the x direction and -5 units in the y direction.

Learn more:

You can explore more about reflection at