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mario62
1 month ago
11

Three books (x, y, and z) rest on a table. x is on table, while y is stacked upon x, and z is stacked upon y. the weights of the

books are mx = 4 n, my = 10 n and mz = 5 n. the net force acting on book y is:

Mathematics
1 answer:
Zina [12.3K]1 month ago
4 0
Refer to the visual representation provided below.

The free body diagram for book y indicates:
a force of 5 N exerted by book z, and a reaction force of 5 N from book z;
a force of 10 N acting on book x, with a reaction of 10 N from book x.

Thus, the total downward force acting on book y is
5 + 10 - 10 = 5 N.

Final answer: 5 N, directed downward.

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For three consecutive years, Sam invested some money at the start of the year. The first year, he invested x dollars. The second
AnnZ [12381]

Let’s define x as the amount invested by Sam in the first year.
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For Sam:
2nd year: investment = 5x/2 - 2000
3rd year: investment = x/5 + 1000

The total Sam invested is:
x + (5x/2 - 2000) + (x/5 + 1000)

Next, we can form the expressions for Sally’s investments.
For Sally
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2nd year: investment = 2x - 1500
3rd year: investment = x/4 + 1400

Thus, Sally's total investment is,
total = (3x/2 - 1000) + (2x - 1500) + (x/4 + 1400)

Setting both totals equal gives us:
(x) + (5x/2 - 2000) + (x/5 + 1000) = (3x/2 - 1000) + (2x - 1500) + (x/4 + 1400)

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RESULTS:
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Sally's third year = $1900
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19 days ago
Based on the information below, choose the correct answer.
PIT_PIT [12445]
Hello

the dollar amount of each monthly payment that is interest
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the percentage of the total payments that is total interest
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Hope this information is helpful.
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The range consists of all the valid y values, starting from 5.
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