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Dmitry
2 months ago
9

PLEASE ANSWER! I WILL BRIANLIEST.

Mathematics
1 answer:
Svet_ta [12.7K]2 months ago
5 0
Let x represent the desired warranty duration, thus
P(X < x) = P(z < (x - 12)/(8/12)) = 1 - 0.067 = 0.933
P(z < 12(x - 12)/8) = P(z < 1.498)
12(x - 12)/8 = 1.498
x - 12 = 8(1.498) / 12 = 0.9987
x = 12 - 0.9987 = 11

Thus, they ought to warranty for 11 years to ensure that fewer than 6.7% encounter failures during that timeframe.

production cost = %13
Let p be the price, then
revenue minus the cost of failed units = p - 0.067(13) = p - 0.871
Profit = p - 0.871 - 13 = 5
p - 13.871 = 5
p = 5 + 13.871 = 18.871

Consequently, they need to price each waffle iron at $18.87.
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The table shows ordered pairs of the function y = 16 + 0.5x .
Leona [12618]

Answer: The unknown values x and y correspond to 8 and 20, specifically;

(x, y) = (8, 20)

Step-by-step explanation: The equation y = 16 + 0.5x represents a linear relationship that can be illustrated with a graph. This indicates that values for x and y can be located at various points on the line.

The ordered pairs signify that for each x value, there exists a matching y value.

The values listed in a two-column format for x and y all fulfill the equation y = 16 + 0.5x. Observing the first example, the pair (-4, 14) is presented.

This reveals that when x is -4, y will be 14.

Where y = 16 + 0.5x

y = 16 + 0.5(-4)

y = 16 - 2

y = 14

Thus, the first pair, similar to the other pairs, satisfies the equation.

Consequently, by reviewing the options provided, we can deduce which one fulfills the equation.

(option 1) If x = 0

y = 16 + 0.5(0)

y = 16 + 0

y = 16

(0, 16)

(option 2) If x = 5

y = 16 + 0.5(5)

y = 16 + 2.5

y = 18.5

(5, 18.5)

(option 3) If x = 8

y = 16 + 0.5(8)

y = 16 + 4

y = 20

(8, 20)

Our calculations confirm that the third option (8, 20) is the correct ordered pair for x and y.

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Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.950.950, point, 95 pro
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The question appears to be incomplete. Here’s the complete inquiry:

Samir is quite skilled with the gun. When he targets a specific aim at the shooting range, he has a 0.95 probability of striking it. On one occasion, Samir sets out to shoot 10 targets consecutively.

If he has the same chance of hitting each of the 10 targets, what is the likelihood that he will miss at least one?

Response:

40.13%

Step-by-step breakdown:

Let 'A' represent the event of successfully hitting all targets in 10 trials.

The complement of 'A' is \overline A=\textrm{Missing a target at least once}

Now, since Samir has a consistent probability of hitting each target at 0.95.

Now, P(A)=0.95^{10}=0.5987

We know that the combined probability of an event and its complement equals 1.

<pThus, P(A)+P(\overline A)=1\\\\P(\overline A)=1-P(A)\\\\P(\overline A)=1-0.5987\\\\P(\overline A)=0.4013=40.13\%

Consequently, the probability that he misses at least one target among 10 attempts is 40.13%.

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Answer:

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This z-score indicates that x= 72 is 1.273 standard deviations above the mean.

Step-by-step explanation:

Let’s consider the following details for this question: John's typing speed on a test is assumed to follow a normal distribution. Let X denote the number of words he can type in a minute. Hence, X ~ N(58, 11). It’s important to round the result to three decimal points if needed.

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The formula for the z score is as follows:

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The mean is 58

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