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sveticcg
13 days ago
11

Dave drives to work each morning at about the same time. his commute time is normally distributed with a mean of 45 minutes and

a standard deviation of 5 minutes. the percentage of time that his commute time exceeds 61 minutes is equal to the area under the standard normal curve that lies to the ___ of ___.

Mathematics
1 answer:
AnnZ [9.1K]13 days ago
8 0
The diagram below illustrates the normal distribution curve. The likelihood that his commuting time surpasses 61 minutes is represented by the area under the standard normal curve located to the right of X=61. To determine the z-score, we standardize X=61.
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babunello [8426]
The question is as follows:
<span>In what ways does the graph of g(x)=1/x-5+2 differ from the graph of the parent function f(x)=1/x?
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Solution:
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The given function ⇒ g(x) = \frac{1}{x-5} +2

The parent function of the provided function ⇒ f(x)= \frac{1}{x}

After graphing both equations, as illustrated in the attached image.
It can be concluded that
<span>g(x) is translated 5 units to the right and 2 units upwards from f(x).
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Thus, the correct answer is option 2
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6 0
22 days ago
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At a certain company, loan agents are paid based on the number of loans they close in a day. Based on company records, the numbe
Zina [9184]

Answer:

C. The mean daily salary is not above $350 per day

Step-by-step explanation:

The calculation is displayed below:

Y = a + bX

where,

Y = earnings of a randomly chosen agent

a = $150

b = $50

X = number of loans closed

Now

E(x) = (1 × 0.05) + (2 × 0.10) + (3 × 0.22) + (4 × 0.30) + (5 × 0.18) + (6 × 0.12) + (7 × 0.03)

= 3.94

Consequently,

E(y) = $150 + ($50 × 3.94)

= $347

therefore, option C is incorrect

4 0
27 days ago
Read 2 more answers
Igor recently immigrated to the UK. He was an experienced surgeon in his country but had to re-do his medical training in order
AnnZ [9117]

Answer:

a) The outlier is the point located at the bottom right of the graph

b) The plotted points resemble a line that has a positive gradient

c) By conducting correlation analysis, we can determine the strength of the correlation

Step-by-step explanation:

a) The problem presents a scenario where Igor, who has recently moved, is experienced but needs to retrain medically to practice in the UK

Thus, he corresponds to the outlier situated nearest to the graph's bottom right

b) According to the scatter graph, there's a direct relationship showing that as a doctor's age increases, their annual salary tends to climb as well

Referencing the graph:

Age      Salary

22        £28000

26        £30000

34        £44000

38        £42000

42        £30000

42        £46000

50        £55000

The data points follow a line demonstrating the proportional increase of salary with age.

c) To reinforce this conclusion's reliability, correlation analysis should be conducted to ascertain the relationship between age and annual incomes.

4 0
1 month ago
Who is sigma Lazyeight?
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Sigma Lazyeight is known as the head of an evil genius terrorist organization.
3 0
14 days ago
Read the proof. Given: m∠H = 30°, m∠J = 50°, m∠P = 50°, m∠N = 100° Prove: △HKJ ~ △LNP Statement Reason 1. m∠H = 30°, m∠J = 50°,
zzz [9093]

Answer:

2. m\angle H+m\angle J +m\angle K =180^{\circ}

Reason: the total sum of all angles inside any triangle equals 180º.

Step-by-step explanation:

1) Organization

Statement 1. m∠H = 30°, m∠J = 50°, m∠P = 50°, m∠N = 100° 1. Reason: given

2) Given that the sum of all internal angles in any triangle is always 180º, similar to the formula. N represents the number of sides of a triangle:

S_{i}=180^{\circ}(n-2)\rightarrow 180(3-2) \therefore S_{i}=180^{\circ}

3) We can also state

m\angle K=180^{\circ}-(m\angle H+m\angle J)\\m\angle K=180^{\circ}-\left ( 30^{\circ}+50^{\circ} \right )\\m\angle K=100^{\circ}

Like in the other triangle:

m\angle L=180^{\circ}-(m\angle N+m\angle P)\\m\angle L=180^{\circ}-\left ( 100^{\circ}+50^{\circ} \right )\\m\angle L=30^{\circ}

4) Therefore,

2. m\angle H+m\angle J +m\angle K =180

Reason: The total of the internal angles is equal to 180º.

8 0
24 days ago
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