Part A
To identify the values of x that make 2x−1 positive
⇒ 2x - 1 > 0
⇒ 2x > 1
⇒ x > 
As a result, for any x greater than

, the expression 2x-1 is positive
Part B
To find values of y making 21−37 negative
⇒ 21-3y < 0
⇒ 21 < 3y
⇒ 7 < y
Thus, for all y values exceeding 7, the expression 21-3y is negative
Part C
To identify values of c that digit 5−3c greater than 80
⇒ 5-3c > 80
⇒ -3c > 75
⇒ -c > 25
⇒ c < -25
Therefore, for values of c less than -25, the expression 5-3c surpasses 80
Answer:
E 240
Step-by-step explanation:
Mean of the geometric distribution = (1- p) / p
16 = (1 - p) / p
16p = 1 - p; 17p = 1; thus, p = 1/17 = 0.058
Standard Deviation = (1 - p) / p^2
= (1 - 0.058) / (0.058)^2
0.942 / 0.003364
= 280, which is closest to 240