Answer:
To find the number of genuine solutions for a system of equations consisting of a linear equation and a quadratic equation
1) With two variables, say x and y, rearrange the linear equation to express y, then substitute this y in the quadratic equation
After that, simplify the resulting equation and determine the number of real roots utilizing the quadratic formula, 
for equations of the type 0 = a·x² - b·x + c.
When b² exceeds 4·a·c, two real solutions emerge; if b² equals 4·a·c, there will be a single solution.
Step-by-step explanation:
Answer:
The attached figure illustrates the graph.
Step-by-step explanation:
Let
x represents the count of open acres
y depicts the total developed acres
It is established that
corresponds to inequality A
corresponds to inequality B
Keep in mind that
if the open acres, x, is limited to a maximum of 1, then it follows that x must adhere to ≤ 1
The system of equations can be solved by graphing
The solution is found in the shaded area (Note Negative acreage counts are not permissible)
The attached figure serves as a visual representation.
The shape of the graph created by these data points indicates it correlates best with a quadratic function.
Answer:
Detailed solution:
Given:
The problem to solve is:
Convert the equation into the standard quadratic form 
, where 
represent constants.
So, by adding 
to both sides, we get:
Note that 
.
The roots of this quadratic are found by applying the quadratic formula given as:
Substitute into the formula and calculate for 
.
Hence, the roots are:
The equations 13x + 15y = 55.50 and 46x + 16y = 131.50 can be utilized to find out the cost per pound for both bananas and grapes, where x represents the price for bananas and y denotes the price for grapes.
