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laila
2 months ago
6

Let x = 8.99999 . (a) Is x < 9 or is x = 9? x < 9 It is neither; x > 9 x = 9 x < 9 and x = 9 It cannot be determined

. (b) Sum a geometric series to find the value of x. x = (c) How many decimal representations does the number 9 have? decimal representations (d) Which numbers have more than one decimal representation? the integers the rational numbers except for 0 all rational numbers that have a terminating decimal representation except for 0 all integers except for 0 all real numbers
Mathematics
1 answer:
tester [12.3K]2 months ago
4 0

Answer: idk

Step-by-step explanation:

idk

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If 30,000 cm2 of material is available to make a box with a square base and an open top, what is the largest possible volume (in
Inessa [12570]

Answer:

The highest achievable volume for the box is 2000000 cubic meters.

Step-by-step explanation:

Below is an outline of the volume (V), measured in cubic centimeters, and surface area (A_{s}), measured in square centimeters, for a box featuring a square base:

A_{s} = l^{2}+h\cdot l (1)

V = l^{2}\cdot h (2)

Where:

l - The length of the base's side, in centimeters.

h - The height of the box, in centimeters.

Using (2), we isolate h in the formula:

h = \frac{V}{l^{2}}

Then, we substitute into (1) and simplify the outcome:

A_{s} = l^{2}+ \frac{V}{l}

A_{s}\cdot l = l^{3}+V

V = A_{s}\cdot l -l^{3} (3)

Next, we calculate the first and second derivatives of this expression:

V' = A_{s}-3\cdot l^{2} (4)

V'' = -6\cdot l (5)

If V' = 0 and A_{s} = 30000\,cm^{2}, then we find that the critical value for the base's side length is:

30000-3\cdot l^{2} = 0

3\cdot l^{2} = 30000

l = 100\,cm

Subsequently, we assess this outcome using the second derivative's expression:

V'' = -600

According to Second Derivative Test, this critical value signifies an absolute maximum. Consequently, the largest volume obtainable for the box is:

V = 30000\cdot l - l^{3}

V = 2000000\,cm^{3}

The highest achievable volume for the box is 2000000 cubic meters.

4 0
1 month ago
A sandbox is 2.5 m wide and 3.4 m long.
zzz [12365]

Answer:

2.55 cubic meters of sand

Step-by-step explanation:

The inquiry focuses on how much sand is needed to completely fill the sandbox. As it is a three-dimensional shape, the concept of 'Volume' is applicable. Volume is determined through the formula L × W × H. By substituting the relevant variables into this equation, you arrive at the final solution. I hope this offers clarity!

5 0
2 months ago
The name of the lesson is "Using Trigonometric Laws" The two non-parallel sides of an isosceles trapezoid are each 7 feet long.
AnnZ [12381]
The diagonal measures 20.68 ft; the shorter base is 17.21 ft. To understand this, we recognize that with base angles summing to 140°, each angle is 70°, given the isosceles trapezoid's properties. We can apply the Law of Cosines to find the diagonal's length, denoted as d. The length of the diagonal determines to be d = 20.68 ft. Determining the shorter base is somewhat more complex. By drawing an altitude from the upper vertices to the base, which measures 22 ft, we create two similar smaller right triangles requiring us to find the height and base measures related to each of the 70-degree angles and the hypotenuse of 7. By working through the calculations for height and base from one triangle, we subsequently find that 22 minus twice the base measure gets us to the shorter base's measure, arriving at x = 17.21 ft.
4 0
2 months ago
Tanmay had some chocolates with him. He gave one-third of them to Akash and one-fifth of them to Sharad. Tanmay could do so with
babunello [11817]

Answer:

Possible values for X include;

15, 30, 45, 60, and so on

Step-by-step explanation:

The parameters provided are

Number of chocolates Tanmay possessed = X

Number of chocolates given to Akash = 1/3 × X

Number of chocolates given to Sharad = 1/5 × X

Consequently, since both 3 and 5 divide X,

3 × 5 = 15 is the smallest single factor of X.

Thus, the values of X based on this minimum factor are as follows;

15 × 1 = 15

15 × 2 = 30

15 × 3 = 45

15 × 4 = 60

Therefore, potential values for X form an arithmetic series: a + (n - 1) × d

Where:

a = 15

n = 1, 2, 3, 4,...

d = 15

This results in;

15, 30, 45, 60

7 0
2 months ago
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