Triangle KLM was dilated according to the rule

Given:

It is stated that

PQ ⊥ PS and

∠QPR = 7x-9

∠RPS = 4x+22

To find the measure of ∠QPR.

Formula

According to the problem PR sits between PQ and PS,

Consequently,

∠QPR+∠RPS = 90°

Now,

Inserting the values for ∠RPS and ∠QPR yields

or,

or,

or,

or,

Substituting the value of into ∠QPR gives us

∠QPR =

or, ∠QPR =

So,

The measure of ∠QPR is 40°.

You can utilize the Pythagorean theorem expressed as a^2 + b^2 = c^2... if b is unknown, you can rearrange the formula. Hence, c^2 - a^2 = b^2. Squaring 47 gives 2209 and squaring 13 yields 169... Subtracting gives you 2209-169, which results in 2040. Taking the square root of that yields approximately 45.166359, which can be rounded to 45 or as 45.167 when expressed to two decimal places. I hope this helps!:)

Answer:

For a 90º clockwise rotation, the vertex q' (–3, 4) maps to q(4, 3).

According to the 90º counterclockwise rotation rule, q' (–3, 4) transforms to q(–4, –3).

Step-by-step explanation:

Given the rectangle with vertices r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4),

Find the image of vertex q after a 90º rotation.

The rotation rules are:

90º clockwise: (x, y) → (y, –x)

90º counterclockwise: (x, y) → (–y, x)

Applying the clockwise rule to q'(–3, 4) yields q(4, 3).

Applying the counterclockwise rule to q'(–3, 4) yields q(–4, –3).

Thus, clockwise rotation of q' (–3, 4) results in q(4, 3),

and counterclockwise rotation results in q(–4, –3).