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12 days ago

- In the following diagram of triangle QRS, QR = 8 and QS = 17. Determine the value of sin Q. Show how you

Mathematics

1 answer:

PIT_PIT [9.1K]12 days ago

5 0

Response:

$SinQ=\frac{15}{17}$

Step-by-step explanation:

We create the right triangle as illustrated in the attached image.

Δ QRS

Here, R represents the right angle

Given

QR = 8

QS = 17

Using the Pythagorean Theorem, we can determine RS:

$QR^2+RS^2=QS^2\\8^2+RS^2=17^2\\RS^2=17^2-8^2\\RS^2=225\\RS=\sqrt{225}\\RS=15$

Currently, the Sine ratio is known as:

$Sin(\theta)=\frac{Opposite}{Hyotenuse}$

Where $\theta$ signifies the angle (in this case, angle Q)

The side opposite is RS (which measures 15)

While the hypotenuse is QS (which equals 17)

At this point,

$SinQ=\frac{15}{17}$

This is the value of SinQ.

We don't require the angle, so we will conclude here.

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Step-by-step explanation:

El perímetro de un rectángulo está dado por:

P = 2*L + 2*A

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Como sabemos que un lado es 6cm más largo que el otro, podemos expresar esto como:

L = A + 6cm.

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Sustituyendo la primera ecuación en la segunda tenemos:

28cm = 2*(A + 6cm) + 2*A

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Answer:

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