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lubasha
20 days ago
15

Sherburne Snow Removal's cost formula for its vehicle operating cost is $2,510 per month plus $371 per snow-day. For the month o

f March, the company planned for activity of 18 snow-days, but the actual level of activity was 17 snow-days. The actual vehicle operating cost for the month was $8,460. The vehicle operating cost in the flexible budget for March would be closest to:
Business
1 answer:
Scilla [3.2K]20 days ago
8 0
The total cost amounts to $8,817. The expense formula for Sherburne Snow Removal's vehicle is a $2,510 monthly base charge along with an additional $371 for each snowfall day. The actual activity level was 17 snow days. The flexible budget will adjust the standard costs to reflect actual utilization. The calculated fixed costs total $2,510, and the variable costs, multiplied by the number of snow days, amount to $6,307, combining for a total of $8,817.
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Keisha Hunter keeps track of day-to-day operational data to make sure her employer has enough cash to run the business and will
stepan [3001]

Answer:

Financial manager.

Explanation:

The role of financial managers involves maintaining the financial stability of an organization. They are responsible for creating financial statements, overseeing investment strategies, and formulating plans alongside data evaluations aimed at achieving the organization’s long-term financial objectives. Keisha Hunter manages everyday financial data to ensure her employer has sufficient funds for operations and assesses the necessity and timing for opening a second distribution location.

6 0
21 day ago
Suppose the market portfolio's excess return tends to increase by 30% when the economy is strong and decline by 20% when the eco
Mariulka [3175]

Answer: Beta for type I = 0

Beta for type S = 1.5

Explanation:

The anticipated return from a security is adjusted according to its respective beta. If a stock has a beta of 1, it reflects its movement correlating equally with the market.

In this scenario, stock I's returns show no correlation with market fluctuations, thus its beta is ‘0’.

Calculating beta for type S = [45 - (-30)]/[30 - (-20)]

= 75/50 = 1.5

6 0
25 days ago
Suppose Proctor​ & Gamble​ (PG) and Johnson​ & Johnson​ (JNJ) are simultaneously considering new advertising campaigns.
Nady [2956]

Answer:

B. The Nash equilibrium suggests both companies should opt for a low advertising strategy.

Explanation:

Examining the responses from both players reveals the following:

If PG decides on High, then JNJ will achieve the best outcome by choosing Low.

If PG selects Medium, JNJ's optimal choice would still be Low.

Should PG pick Low, JNJ again benefits most by choosing Low.

In the same way,

If JNJ opts for High, PG should choose Low for the highest payoff.

<pif jnj="" goes="" with="" medium="" pg="" will="" also="" gain="" the="" most="" by="" selecting="" low.="">

Finally, if JNJ selects Low, PG still maximizes their payoff with a Low choice.

Consequently, PG has a clear dominant strategy to choose Low, and likewise, JNJ also has a dominant strategy to select Low.

</pif>
5 0
27 days ago
Briefly list and discuss two problems that a purchasing department sometimes has in meeting objectives.
arsen [2965]
A purchasing department may face challenges acquiring a product promptly if it is not immediately available, resulting in delays. Additionally, obtaining a product at an acceptable cost can be problematic, requiring the purchaser to seek alternatives, which can also consume extra time.
6 0
1 month ago
Read 2 more answers
The participants in a television quiz show are picked from a large pool of applicants with approximately equal numbers of men an
arsen [2965]

Answer:

a) P(X \leq 2)= P(X=0)+P(X=1)+P(X=2)

P(X=0)=(11C0)(0.5)^0 (1-0.5)^{11-0}=0.00049

P(X=1)=(11C0)(0.5)^1 (1-0.5)^{11-1}=0.0054

P(X=2)=(11C0)(0.5)^2 (1-0.5)^{11-2}=0.027

After addition we obtained:

P(X \leq 2)= 0.033

b) P(X \geq 2)= 1-P(X

Upon substitution we received:

P(X \geq 2)= =1-[0.00049 +0.0054] = 0.994

c) P(X \leq 1)= 1-P(X

Following our substitution we calculated:

P(X \leq 1)=0.00049 +0.0054= 0.0059

Explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution summarizing the likelihood that a variable will assume one of two independent outcomes under specified parameters. Assumptions for this distribution include that each trial produces a single outcome, all trials maintain the same probability of success, and trials are mutually exclusive, or independent of one another".

Problem solution

Let X signify the random variable of interest "number of women"; in this scenario, we know that:

X \sim Binom(n=11, p=0.5)

The probability mass function for the Binomial distribution is expressed as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) represents combinations and is given by this formula:

nCx=\frac{n!}{(n-x)! x!}

In Part a

In this instance, we seek to identify this probability:

P(X \leq 2)= P(X=0)+P(X=1)+P(X=2)

P(X=0)=(11C0)(0.5)^0 (1-0.5)^{11-0}=0.00049

P(X=1)=(11C0)(0.5)^1 (1-0.5)^{11-1}=0.0054

P(X=2)=(11C0)(0.5)^2 (1-0.5)^{11-2}=0.027

After addition we obtained:

P(X \leq 2)= 0.033

In Part b

For this scenario we aim for this probability:

P(X \geq 2)

Utilizing the complement rule, we arrive at:

P(X \geq 2)= 1-P(X

After substitution we arrived at:

P(X \geq 2)= =1-[0.00049 +0.0054] = 0.994

In Part c

In this instance, we are looking for this probability:

P(X \leq 1)

Applying the complement rule yields:

P(X \leq 1)= 1-P(X

After substitution, we computed:

P(X \leq 1)=0.00049 +0.0054= 0.0059

6 0
10 days ago
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