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Andrews
1 month ago
9

True or False: The endpoints of a polygon must conform to snap points, whereas the edges of an area are not confined by snap poi

nts.
Mathematics
2 answers:
lawyer [12.5K]1 month ago
8 0

Answer: False, believe me on this.

Detailed explanation:

Inessa [12.5K]1 month ago
3 0

In this scenario, it's important to remember that a polygon is a closed geometric figure made up of n sides, typically connected by straight line segments.

To calculate the area of a shape, the figure must be closed.

Thus, the boundaries of an area are fixed by snap points.

Answer:

FALSE

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Alan is conducting a survey to find out the type of art preferred by students in the town’s high school. Identify the population
Svet_ta [12734]

Response:

Alan's survey aims to determine the art preferences among students at the local high school.

To conduct a thorough investigation, he needs to consider all students in the school as the target population since that is his goal.

Nevertheless, in many cases involving statistical studies, it's impractical to include the entire population. In such instances, a sample that accurately reflects the overall student body is employed.

This sample is a subset of the population and must share the same characteristics and attributes; otherwise, the findings may be skewed.

Thus, a feasible sample would consist of a specific number of students from each grade level, including freshmen, sophomores, juniors, and seniors. This approach ensures the sample accurately represents the larger population.

8 0
1 month ago
Read 2 more answers
The line segments of a cube include edges, the diagonals of the faces, and the diagonals through the interior of the cube. Which
lawyer [12517]
The diagonal that crosses the interior of the cube is the longest segment. The hypotenuse corresponds to the longest side in a right triangle. In this case, the cube's diagonal serves as the hypotenuse of a right triangle, with the legs being the diagonal of one of its faces and one of its edges. The edges are the shortest sections and function as the legs of a right triangle where the face's diagonal acts as the hypotenuse.
0 0
23 days ago
Read 2 more answers
If Ana devotes all her time to making fudge, she can make 3 pounds of fudge an hour, and if he devotes all her time to making to
lawyer [12517]

Answer: Ana should produce more fudge, and Leo should produce more toffee.

Step-by-step explanation:

Comparative advantage defined: A person or country has a comparative advantage producing a good if their opportunity cost for it is lower than someone else's.

In this case, Ana and Leo will both benefit if they focus on the product for which they have the lower opportunity cost.

(a) Ana’s production possibilities:

If she spends all her time making fudge: 3 pounds; or toffee: 2 pounds.

Opportunity cost of 1 pound fudge = 2/3 = 0.66 pounds toffee

Opportunity cost of 1 pound toffee = 3/2 = 1.5 pounds fudge

(b) Leo’s production opportunities:

All time making fudge: 4 pounds; or toffee: 5 pounds.

Opportunity cost of 1 pound fudge = 5/4 = 1.25 pounds toffee

Opportunity cost of 1 pound toffee = 4/5 = 0.8 pounds fudge

Since Ana’s opportunity cost for fudge is lower than Leo’s, she should specialize in fudge production.

Conversely, Leo has a lower opportunity cost for toffee, so he should focus on producing toffee.

7 0
1 month ago
Calculating conditional probabilities - random permutations. About The letters (a, b, c, d, e, f, g) are put in a random order.
AnnZ [12381]

A="b is situated in the center"

B="c lies to the right of b"

C="The letters def occur sequentially in that arrangement"

a) b can occupy 7 positions; however, only one of these is the center. Therefore, P(A)=1/7

b) Let X=i; "b holds the i-th position"

Y=j; "c occupies the j-th position"

P(B)=\displaystyle\sum_{i=1}^{6}(P(X=i)\displaystyle\sum_{j=i+1}^{7}P(Y=j))=\displaystyle\sum_{i=1}^{6}\frac{1}{7}(\displaystyle\sum_{j=i+1}^{7}\frac{1}{6})=\frac{1}{42}\displaystyle\sum_{i=1}^{6}(\displaystyle\sum_{j=i+1}^{7}1)=\frac{6+5+4+3+2+1}{42}=\frac{1}{2}

P(B)=1/2

c) Let X=i; "d holds the i-th position"

Y=j; "e occupies the j-th position"

Let Z=k; "f is in the i-th position"

P(C)=\displaystyle\sum_{i=1}^{5}( P(X=i)P(Y=i+1)P(Z=i+2))=\displaystyle\sum_{i=1}^{5}(\frac{1}{7}\times\frac{1}{6}\times\frac{1}{5})=\frac{1}{210}\displaystyle\sum_{i=1}^{5}(1)=\frac{1}{42}

P(C)=1/42

P(A∩C)=2*(1/7*1/6*1/5*1/4)=1/420

P(B\cap C)=\displaystyle\sum_{i=1}^{3} P(X=i)P(Y=i+1)P(Z=i+2)\displaystyle\sum_{j=i+3}^{6}P(V=j)P(W=j+1)=\displaystyle\sum_{i=1}^{3}\frac{1}{6}\frac{1}{7}\frac{1}{5}(\displaystyle\sum_{j=1+3}^{6}\frac{1}{4}\frac{1}{3})=1/420

P(B∩A)=3*(1/7*1/6)=1/14

P(A|C)=P(A∩C)/P(C)=(1/420)/(1/42)=1/10

P(B|C)=P(B∩C)/P(C)=(1/420)/(1/42)=1/10

P(A|B)=P(B∩A)/P(B)=(1/14)/(1/2)=1/7

P(A∩B)=1/14

P(A)P(B)=(1/7)*(1/2)=1/14

Events A and B are independent

P(A∩C)=1/420

P(A)P(C)=(1/7)*(1/42)=1/294

Events A and C are not independent

P(B∩C)=1/420

P(B)P(C)=(1/2)*(1/42)=1/84

Events B and C are not independent

8 0
1 month ago
Energy drink consumption has continued to gain in popularity since the 1997 debut of Red Bull, the current leader in the energy
tester [12383]

Answer:

1. 3.767

2. 0.145

Step-by-step explanation:

Define X as the exam scores and Y as the number of drinks.

X     Y   X-Xbar    Y-Ybar   (X-Xbar)(Y-Ybar)    (X-Xbar)²       (Y-Ybar)²    

75    5    -2.3          2.3          -5.29                      5.29              5.29

92    3     14.7         0.3           4.41                       216.09           0.09

84    2     6.7         -0.7           -4.69                     44.89             0.49

64    4     -13.3        1.3           -17.29                     176.89           1.69

64    2     -13.3       -0.7           9.31                       176.89           0.49

86    7     8.7           4.3           37.41                     75.69            18.49

81     3     3.7           0.3           1.11                         13.69             0.09

61     0    -16.3        -2.7           44.01                     265.69          7.29

73    1      -4.3         -1.7            7.31                        18.49             2.89

93    0    15.7         -2.7           -42.39                    246.49          7.29

sumx=773, sumy=27, sum(x-xbar)(y-ybar)= 33.9, sum(X-Xbar)²= 1240.1,sum(Y-Ybar)²= 44.1

Xbar=sumx/n=773/10=77.3

Ybar=sumy/n=27/10=2.7

1.

Cov(x,y)=sxy=\frac{Sum(X-Xbar)(Y-Ybar)}{n-1}

Cov(x,y)=33.9/9

Cov(x,y)=3.76667

Thus, the sample covariance of exam scores and energy drink consumption is 3.767

2.

Cor(x,y)=r=\frac{Sum(X-Xbar)(Y-Ybar)}{\sqrt{Sum(X-Xbar)^2sum(Y-Ybar)^2} }

Cor(x,y)=r=\frac{33.9}{\sqrt{(1240.1)(44.1)} }

Cor(x,y)=r=33.9/233.85553

Cor(x,y)=r=0.14496

The sample correlation coefficient for the relationship between exam scores and energy drink consumption is 0.145.

7 0
1 month ago
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