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andre
2 months ago
6

The weight of a population of yeast is given by a differentiable function y, where y(t) is measured in grams and t is measured i

n days. The weight of the yeast population increases according to the equation dy/dt= ky, where k is a constant. At time t=0, the weight of the yeast population is 120 grams and is increasing at the rate of 24 grams per day. Which of the following is an expression for y(t)?
a. 120e^24t
b. 120e^t/5
c. e^t/5+119
d. 24t+ 120
Mathematics
1 answer:
Leona [12.6K]2 months ago
6 0

Answer:

b) y = 120e^{t/5}

Step-by-step explanation:

Given that the weight of a yeast population is described by a differentiable function y, representing weight in grams and time t in days. The growth of the yeast population follows this equation:

\frac{dy}{dt} =ky for a constant k.

Separate the variables and integrate:

ln y=k t +C\\y = Ae^{kt}

Utilizing the fact that y = 120 when t=0:

120 = A

y = 120e^{kt}

At t = 1, the growth rate is 24 grams.

That is, 144 = 120e^{k*1}\\k = ln 144/120 = 0.1823~0.2

Therefore, option b, which is:

y = 120e^{t/5}

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