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Darya
2 months ago
8

The total number of degrees, D, in an n-sided polygon is given by the formula D=180(n-2). When Janelle solves for n, she gets n=

D+360/180. Sophie solved the same equation for n and got an equivalent equation. Which of the following could be Sophie’s equation?
n=D/180 +2


n=D/180 -2


n=D-178


n=D-182
Mathematics
2 answers:
AnnZ [12.3K]2 months ago
3 0
<span>D = 180 * (n -2)
D = 180n -360
180n = D +360
n = (D / 180) + 2

Thus, the answer is "A"
Additionally, we can verify this using a square where the total angles add up to 360
n = (D / 180) +2
n = (360 / 180) +2
number of sides = 4
correct

Source:
http://www.1728.org/polygon.htm[[TAG_15]][[TAG_16]][[TAG_17]][[TAG_18]][[TAG_19]][[TAG_20]] </span>
AnnZ [12.3K]2 months ago
3 0
D=180(n-2)
To find n, we start by dividing both sides by 180:
D/180=180(n-2)/180
D/180=n-2
Now, adding 2 to both sides of the equation:
D/180+2=n-2+2
D/180+2=n
So, n=D/180+2

Final answer: First Option n=D/180+2

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An experiment was conducted to record the jumping distances of paper frogs made from construction paper. Based on the sample, th
tester [12383]

Answer:

9.9676 - 2.326*0.5904 =8.594

9.9676 + 2.326*0.5904 =11.341

Step-by-step explanation:

Notation

\bar X is the sample mean

\mu indicates the population mean (the variable of interest)

s signifies the sample standard deviation

n denotes the sample size

Solution to the problem

The mean's confidence interval is derived from the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In this instance, the 9% confidence interval corresponds to:

8.8104 \leq \mu \leq 11.1248

We can determine the mean using the following:

\bar X = \frac{8.8104 +11.1248}{2}= 9.9676

Additionally, the margin of error can be calculated as:

ME= \frac{11.1248- 8.8104}{2}= 1.1572

The margin of error for this situation is expressed as:

ME = t_{\alpha/2}\frac{s}{\sqrt{n}} = t_{\alpha/2} SE

Next, we find the standard error:

SE = \frac{ME}{t_{\alpha/2}}

The critical value for a 95% confidence interval using a normal standard distribution is roughly 1.96, and substituting gives us:

SE = \frac{1.1572}{1.96}= 0.5904

For the 98% confidence interval, the significance corresponds to \alpha=1-0.98= 0.02 and \alpha/2 = 0.01 with a critical value of 2.326, yielding a confidence interval of:

9.9676 - 2.326*0.5904 =8.594

9.9676 + 2.326*0.5904 =11.341

8 0
2 months ago
A sprinter ran a race in 11 seconds. What is the domain of this graph?
lawyer [12517]
The domain is defined as the complete set of values of variable x for which the function is valid. In this case, the x-axis illustrates time in seconds. Therefore, we must determine all possible time values over which distance can be covered or the function is defined. It’s noted that the sprinter completed the race in 11 seconds, and the start time is 0 seconds. Hence, the value of t ranges from 0 to 11. Therefore, the domain encompasses all real numbers from 0 to 11.
4 0
2 months ago
:
babunello [11817]
18.95(0.3 + 0.1) is the formula to use.
6 0
1 month ago
Maureen McIlvoy, owner and CEO of a mail order business for wind surfing equipment and supplies, is reviewing the order filling
lawyer [12517]

Response:

Maureen's null hypothesis is, H₀: p₁ ≥ p₂.

Detailed explanation:

Maureen McIlvoy, as the owner and CEO of a mail-order business specializing in windsurfing gear, is scrutinizing the order fulfillment processes in her warehouses. Her objective is to achieve a 100% shipment rate of orders within 24 hours. Upon examining her warehouse operations, she discovers that both the East coast and West coast warehouses have not met this goal, although the East Coast warehouse has consistently outperformed its counterpart.

To verify this finding, Maureen’s team randomly sampled 200 orders from the West Coast warehouse (population 1) and 400 from the East Coast warehouse (population 2).

Of the sampled 200 orders from the West Coast warehouse, 190 were delivered within the specified time. In contrast, 372 out of 400 orders from the East Coast warehouse were processed within 24 hours.

The hypotheses can be formulated as followed:

H₀: The proportion of timely shipments from the East Coast does not exceed that from the West Coast warehouse, thus, p₁ ≥ p₂.

Hₐ: The proportion of timely shipments from the East Coast warehouse is indeed greater than that from the West Coast warehouse, stated as p₁ < p₂.

Thus, Maureen's null hypothesis becomes, H₀: p₁ ≥ p₂.

8 0
2 months ago
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