Part A:
Considering the best possible outcome
The ideal case occurs if the two missing socks are from the same pair.
Consequently, there are 4 complete pairs remaining.
To choose 2 from the total of 10 socks (5 pairs), the number of combinations is given by 10C2 = 45.
Choosing 2 that are from the same pair means selecting one from 5 pairs, so the count is 5C1 = 5.
Thus, the probability for this best case is 5 / 45 = 1 / 9.
Part B:
Considering the worst-case outcome
This scenario occurs when the two missing socks are from different pairs.
As a result, we have 3 complete pairs left.
The total ways to select 2 socks from 10, again, is 10C2 = 45.
To select 2 that do not belong to the same pair, we calculate as follows: 10C2 - 5C1 = 45 - 5 = 40.
Therefore, the probability for the worst-case scenario is 40 / 45 = 8 / 9.
To calculate this, a specific formula will be necessary. Years = log (total/principal) / [n * log (1 + rate / n)]. Part A) For Calvin: $400 at 5% monthly results in $658.80; Time =? Monthly compounding, n = 12. Thus, Years = log(658.80/400) / [12 * log(1+ (.05/12))]. Subsequently, Years = log(
1.647) / (12 * log(1.0041666667)). Then, Years = 0.21669359917 / 12 * 0.0018058008777. Thus resulting in Years = 0.21669359917 / 0.0216696105. Ultimately, Years ≈ 9.999884362. Part B) For Makayla: $300 at 6% quarterly yields $613.04; Time=? Quarterly compounding, n = 4. Therefore, Years = log(613.04/300) / [4 * log (1 +.06/4)]. This results in Years = log(2.0434666667) / (4 * log(1.015)). Years thus equals 0.31036755784 / (4 * 0.0064660422492), resulting in Years ≈ 11.9999044949. The approximate difference is about 3 years.
For the blue marbles:
16 = 8 * 2 (8 sets containing 2 marbles each)
For the white marbles:
8 = 4 * 2 (4 sets with 2 in each)
8 + 4 = 12
Answer:
The maximum number of groups that Colton can form is 12.
It is understood that
One tens corresponds to the number -----------> 
thus
tens translates to
hence
the result is
220: goodnight, mark me brainliest Explanation: Let M symbolize the count of people who drank milk, while T denotes those who consumed tea. Let x indicate the number who had both milk and tea. Consequently, the count of individuals who drank only milk is represented by n(M ∩ T') = 620 - x, and those who drank only tea is n(M' ∩ T) = 350 - x. Since 800 individuals took part, we have: 620 - x + (350 - x) + x + 50 = 800, simplifying to 1020 - x = 800. Therefore, x = 220. Thus, 220 individuals consumed both beverages.
