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loris
3 days ago
12

A quarter is approximately 0.07 inches thick. A dollar bill is approximately 4.3 × 10-3 inches thick.

Mathematics
1 answer:
lawyer [9.2K]3 days ago
8 0

m = 6.57 and n = -2

Detailed explanation:

To solve this question, convert the thickness of a dollar bill into standard notation and compare the two thicknesses.

0.07 compared to 0.0043 results in 0.0657

0.0657 = 6.57 x 10^-2

Thus, a quarter is thicker than a dollar by 6.57 x 10^-2.

m = 6.57 and n = -2

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Based on daily measurements, Bob's weight has a mean of 200 pounds with a standard deviation of 16 pounds, while Mary's weight h
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Answer:

(C) They have the same coefficient of variation

Step-by-step explanation:

The coefficient of variation (CV) is calculated using the formula:

CV = \frac{\sigma}{\mu}

Where \sigma represents standard deviation and \mu represents the mean.

Bob's average weight is 200 pounds with a standard deviation of 16 pounds

This indicates that \sigma = 16, \mu = 200.

Thus, his coefficient of variation is

CV = \frac{16}{200} = 0.08

Mary's average weight is 125 pounds, with a standard deviation of 10 pounds.

This implies \sigma = 10, \mu = 125

Therefore, her coefficient of variation is

CV = \frac{10}{125} = 0.08

Since both have the same coefficient of variation, the accurate response is.

(C) They have the same coefficient of variation

6 0
24 days ago
Given: ∠ABC ≅ ∠DEF and ∠GHI ≅ ∠DEF Prove: m∠ABC = m∠GHI We are given that angle ABC and are congruent, and that angle GHI and an
AnnZ [9099]

1. Angle DEF

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6 0
1 month ago
What are the domain range and asymptote of h(x)=(1.4)^x+5
Inessa [9000]
The range consists of all the valid y values, starting from 5.
6 0
28 days ago
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Biologists stocked a lake with 240 fish and estimated the carrying capacity (the maximal population for the fish of that species
Inessa [9000]

Answer:

2.30 years

Step-by-step explanation:

The fish population increased threefold in the first year, resulting in 240 * 3 = 720 fish.

(a) The logistic equation can be represented as follows

P = P_0e^{kt}

where P0 = 240 denotes the initial fish count; substituting P = 720 and t = 1 allows us to determine the constant k

720 = 240e^{1k}

e^k = 3

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b) By applying the formula below

P = P_0e^{kt}

with P set to 3000, P0 as 240, and k equal to 1.1, we can compute the duration needed for the population to reach 3000 fish

3000 = 240e^{1.1t}

12.5 = e^{1.1t}

1.1t = ln12.5 = 2.53

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6 0
12 days ago
Sal recorded the number of crackers in each snack-sized package he opened. Which statement must be true according to the box plo
PIT_PIT [9117]

Response:

The data shows skewness, with the minimum amount of crackers in a pack being 7

Detailed explanation:

Hello,

Firstly, the question lacks completeness due to missing information from the box plot, which I have provided to assist you in answering your inquiry.

Considering the details from the attached image, a symmetric distribution would be centered evenly, but that is not the case here.

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7 0
11 hours ago
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