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Misha Larkins
10 days ago
12

The sharks are fed three times a day. During the morning feeding , 2/15 tons of fish is fed. During the afternoon feeding, the w

eight of fish fed will be 1/15 ton more than the fish fed during the morning. If the total weight of fish fed in a day is 1/2 ton, how much is fed during the feeding at night?
Mathematics
1 answer:
zzz [9K]10 days ago
7 0

Answer:

1/6 ton of fish is provided during the night feeding.

Step-by-step explanation:

The fish consumed in the morning is \dfrac{2}{15} tons, and the amount of fish served in the afternoon is \dfrac{1}{15} greater than in the morning. This means

\dfrac{2}{15} +\dfrac{1}{15}

Let’s represent the quantity of fish given at night as x, and if the total fish fed throughout the day equals \dfrac{1}{2}, we have

\dfrac{2}{15}+(\dfrac{2}{15} +\dfrac{1}{15})+x=\dfrac{1}{2}

By summing the numerators on the left side, we derive:

\dfrac{5}{15} +x=\dfrac{1}{2}

and subtracting \dfrac{5}{15} from both sides allows us to isolate x:

x=\dfrac{1}{2} -\dfrac{5}{15}

Since \dfrac{5}{15} =\dfrac{1}{3}, we derive

x=\dfrac{1}{2}-\dfrac{1}{3}

The common denominator for the fractions is 6; hence, we write the equation in the form

x=\dfrac{3}{6}-\dfrac{2}{6}

and simplifying the numerators results in:

\boxed{x=\dfrac{1}{6} }

which indicates the amount of tons fed during the night feeding.

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