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Mashcka
3 months ago
7

How many pairs of whole numbers have a sum of 110

Mathematics
1 answer:
Inessa [12.5K]3 months ago
3 0
Whole numbers include 0, 1, 2, 3, 4, 5, and so forth.
There are 56 pairs of whole numbers that add up to 110, such as:
0 + 110 = 110
1 + 109 = 110
2 + 108 = 110
.
.
.
.
.
55 + 55 = 110
Thus, the total count of pairs is 56.
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7. During a person's commute to school, she spends 10 minutes driving 30 miles per hour (mph) and 5 minutes stopped at red light
Inessa [12570]

Answer:

5 miles in total

Step-by-step explanation:

Given:

Time spent driving = 10 min = 10 / 60 = 1/6 hour

Duration of stop = 5 min

Driving speed = 30 miles per hour

Find:

Complete distance

Computation:

Distance traveled = Speed × time

Distance = 30 × (1/6)

Total distance = 5 miles

5 0
3 months ago
If Machine A makes a yo-yo every five minutes and Machine B takes ten minutes. How many hours would it take them to make 20yo−yo
zzz [12365]
Time required equals 66 2/3 minutes, which is equivalent to approximately 1.11 hours.
4 0
2 months ago
Which are the roots of the quadratic function f(b) = b2 – 75? Select two options. b = 5 StartRoot 3 EndRoot b = Negative 5 Start
zzz [12365]

Answer:

b = 5√3

b = -5√3

Step-by-step explanation:

We have

f(b)=b^{2}-75

Keep in mind, the root of a function corresponds to the value of x at which the function's output is zero.

In this case

The roots of the equation are the b values for which f(b) equals zero.

Thus

For f(b)=0

b^{2}-75=0

b^{2}=75

Take the square root of both sides

b=(+/-)\sqrt{75}

Now simplify

b=(+/-)5\sqrt{3}

b=5\sqrt{3}  and b=-5\sqrt{3}

So we find that

b = 5√3

b = -5√3

8 0
2 months ago
Read 2 more answers
Biologists stocked a lake with 240 fish and estimated the carrying capacity (the maximal population for the fish of that species
Inessa [12570]

Answer:

2.30 years

Step-by-step explanation:

The fish population increased threefold in the first year, resulting in 240 * 3 = 720 fish.

(a) The logistic equation can be represented as follows

P = P_0e^{kt}

where P0 = 240 denotes the initial fish count; substituting P = 720 and t = 1 allows us to determine the constant k

720 = 240e^{1k}

e^k = 3

k = ln3 = 1.1

b) By applying the formula below

P = P_0e^{kt}

with P set to 3000, P0 as 240, and k equal to 1.1, we can compute the duration needed for the population to reach 3000 fish

3000 = 240e^{1.1t}

12.5 = e^{1.1t}

1.1t = ln12.5 = 2.53

t = 2.30 years

6 0
2 months ago
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