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3 months ago

Label the place value 12,354.897

2 answers:

7 0

I'll assume you want the place value of each digit.
12,354.897 (reading left to right)

1 is in the ten-thousands place.

2 is in the thousands place.

3 is in the hundreds place.

5 is in the tens place.

4 is in the ones place.

8 is in the tenths place. (Note the "th" suffix used for positions to the right of the decimal. Also, there is no ones place after the decimal.)

9 is in the hundredths place.

7 is in the thousandths place.

Zina [12.3K]3 months ago

6 0

Begin at the leftmost digit

Ten thousands; then thousands; then hundreds; then tens; then ones; then tenths; then hundreths; then thousandths,

The transformation is a reflection over the x-axis followed by a translation 6 units left and 2 units down.

Step-by-step explanation:

To determine the order of transformations from ΔABC to ΔA"B"C", note that the figure first changes to ΔA'B'C', and then to ΔA''B''C''.

The transition from ΔABC to ΔA'B'C' involves a reflection over the x-axis, as ΔA'B'C' appears as a mirror image flipped vertically.

Next, moving from ΔA'B'C' to ΔA''B''C'' entails shifting the figure left by 6 units and downward by 2 units. This matches a translation by -6 in the x direction and -2 in the y direction.

Thus, the accurate description is:

Reflection across the x-axis followed by a translation of -6 units in x and -2 units in y.

4 0

3 months ago

Read 2 more answers

In 1994, the General Social Survey had a question that asked its participants (that currently smoked) if they had ever tried to

Inessa [12570]

Answer:

The proportion of the population that attempted to stop smoking is 0.8239.

Step-by-step explanation:

In the problem, we are provided with the following details:

Total sample size, n = 142

Individuals who attempted to quit smoking = 117

Parameter:

A parameter represents a numerical descriptor of a population.

The calculation for the population proportion is as follows:

$p = \dfrac{x}{n} \\\\p= \dfrac{117}{142} \\\\p= 0.8239$

The proportion of the population that attempted to stop smoking is 0.8239.

7 0

1 month ago

Concur Technologies Inc is a large expense-management company located in Redmond Washington. The wall street Journal asked Concu

Zina [12379]

Answer:

Let's explore this step-by-step:

Greetings!

Here are the variables

X: daily cost of hotel rooms

Y: expenses for entertainment

Refer to the second attachment for the scatter plot.

The population regression equation can be expressed as E(Yi)= α + βXi

To find the y-intercept and the slope of the regression line, apply the following formulas:

a= Y[bar]-bX[bar] $b= \frac{sum XY-\frac{(sumX)(sumY)}{n} }{sumX^2-\frac{(sumX)^2}{n} }$

In this scenario, n= 9; ∑X= 945; ∑X²= 103325; ∑Y= 1134; ∑Y²= 148804; ∑XY= 123307

Calculating X[bar]= ∑X/n= 945/9= 105

Calculating Y[bar]= ∑Y/n= 1134/9= 126

Thus, it follows that a= 126 - 1.03*105= 17.49 $b= \frac{123307-\frac{945*1134}{9} }{103325-\frac{(945)^2}{9} }= 1.03$

The regression equation is then given by ^Y= 17.49 + 1.03Xi

Slope interpretation: For each unit increase in the daily hotel rate, the expected average spending on entertainment rises by $1.03.

Given that the room rate in Chicago is $128 (X), we can predict the entertainment expenditure (Y) using the estimated regression line:

^Y= 17.49 + 1.03Xi= 17.49 + 1.03*128= 149.33

The anticipated spending on entertainment for Chicago is $149.33

I trust this will assist you!

6 0

2 months ago

A survey asked students whether they have any siblings and pets. the survey data are shown in the relative frequency table.

PIT_PIT [12445]

Response:

The probability that a student has a pet, given they do not have any siblings is:

Option: D ( 60%)

Step-by-step breakdown:

Let A represent the situation where a student lacks a sibling.

Let B signify the occurrence that a student has a pet.

Consequently, A∩B refers to the event in which a student is without siblings but possesses a pet.

Let P denote the chance of an event happening.

We need to determine:

P(B|A)

From our knowledge:

$P(B|A)=\dfrac{P(A\bigcap B)}{P(A)}$

From the data provided:

P(A)=0.25

and P(A∩B)=0.15

Thus,

$P(B|A)=\dfrac{0.15}{0.25}\\\\P(B|A)=\dfrac{3}{5}\\\\P(B|A)=0.6$

which expressed as a percentage is:

$0.6\times 100=60\%$

Therefore, the probability is:

60%

5 0

2 months ago