A set of sweater prices are normally distributed with a mean of 585858 dollars and a standard deviation of 555 dollars.What prop

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Alchen

2 months ago

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A set of sweater prices are normally distributed with a mean of 585858 dollars and a standard deviation of 555 dollars.What prop

ortion of sweater prices are between 48.5048.5048, point, 50 dollars and 606060 dollars?

Business

1 answer:

harina [3.8K] · Answer 1 · 2026-03-17T23:48:02+03:00

The mean is represented as μ = 58 and the standard deviation σ = 5. With given values of x₁ = 48.5 and x₂ = 60, we compute t-values through the formula t = (x₂ - μ) / σ, which leads to t = (60 - 58) / 5 = 0.4, yielding an area of 0.1554 from the normal distribution curve. Similarly, for the lower value, t is computed as (μ - x₁)/ σ, resulting in t = (58 - 48.5) / 5 = 1.9 with an area of 0.4713. Totaling these, the total area under the curve is 0.4713 + 0.1554 equating to 0.6267 or 62.67%.