In Python: import random def simulate_visited_area_codes(): area_codes = [] for i in range(51): num = random.randint(200,1000) area_codes.append(num) visited_codes = [289, 657, 786, 540] count = 0 for i in range(51): for j in range(len(visited_codes)): if area_codes[i] == visited_codes[j]: count+=1 return count print("Visited Areas: " + str(simulate_visited_area_codes())) Explanation: Your question appears to lack many details, and therefore I will make some assumptions. These are: The 50 area codes are stored in the area_codes list, which is populated with randomly generated values. The visited area codes are saved in visited_codes list, initially set as [289, 657, 786, 540]. The subsequent program aims to count and explain the necessary steps.
Answer:
The required number of bits to address 8K words is 13.
Explanation:
Addressable words total 8000, where a word is defined as the smallest unit of memory that can be addressed.
These 8000 words can be accessed using 
units. To find the value of n corresponding to the number of words, you need to calculate
It's clear that 13 bits are necessary to address 8K words.
Response:
For holding the area of a rectangle, the most suitable variable name is area.
please give brainliest
