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Slav-nsk
3 months ago
10

A computer’s memory is composed of 8K words of 32 bits each. How many bits are required for memory addressing if the smallest ad

dressable memory unit is a word?
13

8

10

6

32
Computers and Technology
1 answer:
Natasha_Volkova [1K]3 months ago
7 0

Answer:

The required number of bits to address 8K words is 13.

Explanation:

Addressable words total 8000, where a word is defined as the smallest unit of memory that can be addressed.

These 8000 words can be accessed using 2^{n} units. To find the value of n corresponding to the number of words, you need to calculate

2^2=4\\2^4=16\\2^7=128\\2^{10}=1024\\2^{12}=4096\\2^{13}=8192

It's clear that 13 bits are necessary to address 8K words.

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