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cluponka
2 months ago
7

In a two-point test cross, 36 of the offspring were recombinant types. The remaining 64 offspring were parental types. How many

map units separate the two loci
Biology
1 answer:
vlada-n [2.5K]2 months ago
6 0

Answer:

36

Explanation:

A two-point test cross involves mating an individual with a double heterozygote genotype against a homozygous recessive one to ascertain the recombination frequency between two linked genes. In genetic terms, one map unit (m.u.) is indicative of the genetic distance separating genes for which one (1) of a hundred (100) meiotic products is recombinant. Here, 36 of the progeny exhibited the recombinant phenotype, while the other 64 did not, indicating that the two genes are spaced by 36 mu (64 + 36 = 100 >> 36 mu).

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