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Mazyrski
4 days ago
13

Explain how primate hand features increase fitness and give one example. When writing about your example name the hand feature t

hat you have chosen and explain clearly why it increase fitness in a tree environment.
Biology
1 answer:
enyata [1.7K]4 days ago
5 0
Primates possess hand features like opposable thumbs, enhancing their adaptability to arboreal environments. The thumb, being the widest digit, has mobility that distinguishes it from the other fingers, enabling effective gripping and handling of objects. For instance, monkeys can securely grab branches when navigating from tree to tree.
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If algae populations continue to decline, predict how this might impact the Great Barrier Reef food web.
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I’m not entirely sure...
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3 days ago
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Explain how to focus a microscope using the high-power lens. Include any safety issues you need to be aware of.
enyata [1788]
1) Magnification increases through powers like 10x, 100x, 1000x, and even up to 10,000x.

2) Begin focusing with the lowest magnification lens, usually 10x; once in focus, switch to medium power (100x) and fine-tune using the fine adjustment knob. Avoid using the coarse focus on medium or high powers. Then move to the highest power (typically 1000x), and carefully focus again with the fine knob.

3) To keep the lens clean and prevent dust or fog buildup, proper handling and storage are necessary.
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1 month ago
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Write one scientific question about the organism in the photo. A Field of Sunflowers
11111nata11111 [1806]
What type of sunflower species is depicted, and how efficiently does it conduct photosynthesis? 
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1 month ago
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Suppose a species of bird called the red-crested warbler has a plumage length that is controlled by a single gene. The Plm allel
enyata [1788]

Different allele frequencies are expected in the two groups.

North American:

72 birds altogether => 144 total alleles

From 72, 55 birds have short plumes, hence 17 are short-plumed.

q^2 = (2*17) / 114 = 0.236

Frequency(short plume allele) = q = 0.486

Frequency(long plume allele) = p = 1 - q = 0.514

Thus, from the North American group:

0.486 * 114 = 55 long plume alleles

0.514 * 114 = 59 short plume alleles

South American:

252 birds totaling => 504 alleles

Out of 252 birds, 75 have long plumage, 177 are short-plumed.

q^2 = (2*177) / 504 = 0.702

Frequency(short plume allele) = q = 0.838

Frequency(long plume allele) = p = 1 - q = 0.162

Thus, from this South American group:

0.162 * 504 = 82 long plume alleles

0.838 * 504 = 422 short plume alleles

For the combined population:

55 + 82 = 137 long plume alleles

59 + 422 = 481 short plume alleles

137 + 481 = 618 total alleles

p = 137/618 = 0.222

q = 481/618 = 0.778

The new population reflects the p and q from this blended result. It consists of 1000 individuals. The share of long plumed birds will be the sum of homozygous long plumed and heterozygous long plumed, calculated as: p^2 + 2pq, which you multiply by the population count of 1000 for the outcome.

population size * (p^2 + 2pq) = 1000 * (0.222^2 + 2*0.222*0.778) = 395 birds (final result)

6 0
22 days ago
Maria is concerned because she has been exposed to a small amount of radiation during an X-ray. What is her doctor most likely t
garik1379 [1541]

Response:

Pequeñas cantidades de un mutágeno no suelen afectar la salud

Clarificación:

Los rayos X son una forma de radiación electromagnética utilizada como herramienta de imagen para observar las estructuras internas. La radiación de rayos X se produce cuando una partícula cargada impacta un material a una alta longitud de onda.

La exposición a la radiación de rayos X se ha demostrado que causa serios problemas de salud, ya que se conocen por inducir mutaciones, es decir, son mutagénicos, especialmente si se presentan en grandes cantidades o dosis. Por lo tanto, en el caso de María, quien estuvo expuesta a una pequeña cantidad de radiación por rayos X, es probable que el médico le informe que pequeñas cantidades de un mutágeno (rayos X) generalmente no tienen un impacto en la salud.

3 0
16 days ago
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