Which recursive formula can be used to generate the sequence below, where f(1) = 3 and n ≥ 1? 3, –6, 12, –24, 48, … f (n + 1) = –3 f(n ) f (n + 1) = 3 f(n ) f (n + 1) = –2 f(n ) f (n + 1) = 2 f(n)
2 answers:
What recursive formula applies to generate the following sequence where f(1) = 3 and n ≥ 1?
3, –6, 12, –24, 48
The applicable recursive formula for this sequence is
f(n + 1) = –2 f(n)
When n=1, f(n) equals 3
Now when n = 2
f(2) = -2 (3) = -6
When n = 3
f(3) = -2 (-6) = 12, and this pattern continues.
The formula to recursively establish the sequence is: f(n+1) = -2f(n) Let's consider an example: If we set f(n) = 12 to find f(n+1), it should yield -24 Using the formula, the result would be: f(n+1) = -2*12 = -24. I hope this is the information you were seeking and that it assists you.
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