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kotegsom
14 days ago
9

The average length of time that three lawn-service mowers operate on a given day is 930 minutes. None of the mowers operates for

less than 900 minutes. What is the greatest possible length of time any of the mowers operates?A. 990
B. 950
C. 960
D. 900
E. 930
Mathematics
1 answer:
AnnZ [3.9K]14 days ago
3 0

Answer:

The answer is A. 990.

Step-by-step explanation:

To determine the maximum duration that any of the mowers can run.

The three lawn-service mowers have an average operating time of 930 minutes.

Thus, the overall duration for the three lawn mowers is 930\times 30=2790\ minutes.

The shortest time any mower runs is 900 minutes.

To find the longest operating time of any mower:

Let x represent the maximum operating time for any of the mowers.

Since any of the mowers works the longest time.

Consequently, the remaining two mowers operate at the minimum time.

Based on the question:

x+900+900=2790

x+1800=2790

After subtracting 1800 from both sides:

x=2790-1800

x=990.

Thus, the maximum potential operating time for any mower is 990 minutes.

Consequently, the answer is A. 990.

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lawyer [4039]

Answer: Ana should produce more fudge, and Leo should produce more toffee.

Step-by-step explanation:

Comparative advantage defined: A person or country has a comparative advantage producing a good if their opportunity cost for it is lower than someone else's.

In this case, Ana and Leo will both benefit if they focus on the product for which they have the lower opportunity cost.

(a) Ana’s production possibilities:

If she spends all her time making fudge: 3 pounds; or toffee: 2 pounds.

Opportunity cost of 1 pound fudge = 2/3 = 0.66 pounds toffee

Opportunity cost of 1 pound toffee = 3/2 = 1.5 pounds fudge

(b) Leo’s production opportunities:

All time making fudge: 4 pounds; or toffee: 5 pounds.

Opportunity cost of 1 pound fudge = 5/4 = 1.25 pounds toffee

Opportunity cost of 1 pound toffee = 4/5 = 0.8 pounds fudge

Since Ana’s opportunity cost for fudge is lower than Leo’s, she should specialize in fudge production.

Conversely, Leo has a lower opportunity cost for toffee, so he should focus on producing toffee.

7 0
14 days ago
Sal is trying to determine which cell phone and service plan to buy for his mother. The first phone costs $100 and $55 per month
AnnZ [3900]

Answer:

a) The first inequality is 100 + 55x > 150 + 51x;

b) The final inequality results in x > 12.5

c) Sal's mother will need to use the second phone for at least 13 months.

Step-by-step explanation:

a) Let x represent the number of months.

1. The first phone is priced at $100, with a monthly fee of $55 for unlimited use, leading to a total cost of $(100 + 55x) for x months.

2. The second phone costs $150 with a monthly fee of $51 for unlimited use, resulting in a total of $(150 + 51x) for x months.

3. For the second phone to be cheaper, we set up the inequality:

150 + 51x < 100 + 55x

which simplifies to

100 + 55x > 150 + 51x

b) Now solve this:

55x - 51x > 150 - 100

4x > 50

so x > 12.5

c) This means Sal's mother has to retain the second phone for at least 13 months (since x > 12.5).

8 0
12 days ago
Read 2 more answers
Write the number 0.21212121.. as a fraction let x=
AnnZ [3900]
To work with the repeating decimals, note that since there are two digits repeating, you will be using a 1 followed by two zeros, which is 100. This factor will be important for subsequent calculations.

Let’s denote the repeating decimal as x.

Thus, you can write

x = 0.212121...

Now, if you multiply this equation by 100, you can write it on top of the previous equation.
This results in:

100x = 21.212121...
x = 0.212121...

Next, set up a subtraction by taking the second equation from the first:

100x = 21.212121...
x = 0.212121...
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99x = 21

Solving for x involves dividing both sides by 3:

33x = 7

Then, divide both sides by 33:

x = 7/33

Thus, we conclude that the repeating decimal 0.212121... equates to the fraction 7/33.

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8 days ago
Cuantos paquetes de 10 vasos ocupo para empacar 1367 vasos
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137 paquetes de vasos, aunque el último solo tiene 7 vasos, es necesario para asegurar que no queden sin empacar.
8 0
4 days ago
How much would it cost to buy 100 shares in ODX group Inc and 300 shares
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Complete Question

The entire question can be found in the first uploaded image

Answer:

The expense for acquiring 100 shares of ODX group Inc and 300 shares of peer Comms Lts is

         C  =  \$ 775

Step-by-step explanation:

   From the chat, the expense for 100 shares of ODX is \$175

    The price of 100 shares of peer Comms Lts is \$ 200

Thus, the cost for 300 shares of peer Comms Lts amounts to k  =  3 * 200 =  \$ 600

Overall, the total cost for 100 shares of ODX group Inc and 300 shares of peer Comms Lts can be calculated as

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           C  =  \$ 775

 

 

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18 days ago
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