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erastova
2 months ago
7

A stadium asked for $760,000 for naming rights. During a bidding war for the stadium naming rights, one company bid 7% more than

the amount requested, and a second company bid 2% more than what that company bid. How much did the second company bid
Mathematics
1 answer:
AnnZ [12.3K]2 months ago
8 0

Response:

\$\ 829464

Detailed explanation:

First company bid:

The bid is 7\% more

7\% of 760000=\frac{7}{100}\times760000=53200

Bid of first =760000+53200=813200

Second company bid:

The second company’s bid is 2\% higher than the first

2\% of the first bid =\frac{2}{100}\times 813200=16264

As a result, the second company's bid is =813200+16264=829464

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Svet_ta [12734]

Hope this will assist you....

6 0
3 months ago
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A software engineer creates a LAN game where an 8 digit code made up of 1,2,3,4,5,6,7,8 has to be decided on, universal code . T
PIT_PIT [12445]

Respuesta:

0.0143 = 1.43% de probabilidad de que los primeros 4 dígitos del código sean números pares.

Explicación paso a paso:

Arreglos de elementos n:

El número de arreglos posibles de n elementos se determina por:

A_{n} = n!

Probabilidad:

La probabilidad se calcula dividiendo el número de resultados deseados por el número total de resultados.

En esta pregunta:

Resultados deseados:

Los primeros cuatro dígitos son pares (2, 4, 6 y 8 son pares, así que se consideran 4 elementos).

Los últimos cuatro dígitos son impares (1, 3, 5 y 7 son impares, por lo que los últimos cuatro elementos son también arreglos de 4 elementos). Entonces

D = 4!*4! = 24*24 = 576

Resultados totales:

Arreglos de 8 dígitos. Así que

T = A_{8} = 8! = 40320

Probabilidad:

p = \frac{D}{T} = \frac{576}{40320} = 0.0143

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3 0
1 month ago
Which of the following is an even function g(x) = (x – 1)2 + 1g(x) = 2x2 + 1g(x) = 4x + 2g(x) = 2x
babunello [11817]
An even function can be reflected over the y-axis and still remain unchanged.
Example: y=x^2
On the other hand, an odd function can be reflected around the origin and also remains unchanged.
Example: y=x^3


A straightforward method to determine this is:

if f(x) is even, then f(-x)=f(x)
if f(x) is odd, then f(-x)=-f(x)


Hence, for an even function
substitute -x in for each and check for equivalence
make sure to fully expand the expressions
g(x)=(x-1)^2+1=x^2-2x+1+1=x^2-2x+2 is the original expression
g(x)=(x-1)^2+1
g(-x)=(-x-1)^2+1
g(-x)=(1)(x+1)^2+1
g(-x)=x^2+2x+1+1
g(-x)=x^2+2x+2
Not the same, as the original contains -2x
Therefore, it is not even
g(x)=2x^2+1
g(-x)=2(-x)^2+1
g(-x)=2x^2+1
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g(x)=4x+2
g(-x)=4(-x)+2
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g(x)=2x²+1 is the confirmed even function.
8 0
2 months ago
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when joe bowls he can get a strike 60% of the time, what is the probability jow will get at least 3 strikes out of 4 tries?
Leona [12618]
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8 0
2 months ago
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babunello [11817]
18.95(0.3 + 0.1) is the formula to use.
6 0
1 month ago
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