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Lina20
9 days ago
13

Which classification best represents a triangle with side lengths 6 cm, 10 cm, and 12 cm? acute, because 62 + 102 < 122 acute

, because 6 + 10 > 12 obtuse, because 62 + 102 < 122 obtuse, because 6 + 10 > 12
Mathematics
2 answers:
lawyer [9.2K]9 days ago
7 0
The Pythagorean theorem asserts that
the sum of the squares of the two shorter sides (legs) of a right triangle equals the square of the longest side.

A related principle from this theorem is useful to address this issue:
If the total of the squares of the shorter sides of a triangle surpasses the square of the longest side, the angle in question is acute...... (case 1)
On the other hand, if the total of the squares of the shorter sides is less than that of the longest side, the triangle is obtuse......(case 2)

In this case
6^2+10^2 = 36+100=136 <12^2=144
Thus, this is case 2, indicating that the triangle is obtuse.
PIT_PIT [9.1K]9 days ago
3 0

The classification is C, xotwod

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The area of the postcard is 24 square inches. What is the width b of the message (in inches)?
Leona [9271]
Area of a rectangle = length x width
For this postcard:
length = 4 in
width = (3+b) in
area = 24 in^2

Substitute into the area formula:
24 = 4 x (3+b)
24 = 12 + 4b
24 - 12 = 4b
12 = 4b
b = 3 in

Therefore:
the length of the postcard = 4 inch
the width of the postcard = b+3 = 3 + 3 = 6 inch
4 0
1 month ago
Devon purchased a new car valued at $16,000 that depreciated continuously at a rate of 35%. Its current value is $2,000. The equ
Leona [9271]

Initial cost = 16000
depreciation rate = 35%
remaining value = 2000
depreciation over one year = 16000*35% = 5600
5600*2 = 11200 + 5600*6\12 = 2000
The car is aged 2.5 years, accounting for two full years and an additional half year of depreciation.

7 0
1 month ago
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The proof diagram to complete the question state the missing reason in the proof for the letter given
tester [8842]

ANSWER

Initially, it was established that line p is parallel to line r.

To begin with the proof:

As stated in the prompt:

∠1 ≈∠5

∠1 and ∠5 are corresponding angles.

Utilizing the property of corresponding angles,

if two lines are intersected by a transversal such that the corresponding angles are


congruent, then those lines must be parallel.


In the diagram, q acts as the transversal.

Thus, based on this characteristic,

line p is parallel to line r.

Proof of 1(a)

REASON

Vertically opposite angle

When two lines intersect, the angles formed are referred to as vertically opposite angles.

Therefore,

∠4 and ∠1 are vertically opposite angles,

hence,

∠4 ≈∠1

Proof of 2(b)

REASON

Alternate interior angle

The angles situated on either side of the transversal, within the two lines, are termed alternate interior angles. When two parallel lines are crossed by a transversal, the alternate interior angles produced will be congruent.

Since line p is parallel to line r (as proven above)

and q is the transversal,

then

∠4 ≈∠5

Thus, it is established.

Proof of 3 (c)

Given that ∠4 ≈ ∠5 (as demonstrated above)

REASON

If two lines are intersected by a transversal such that the alternate interior angles are congruent, then those lines are parallel.

Thus, based on the previously mentioned property,

line p is parallel to line r.

Therefore, it is proven.







4 0
27 days ago
Read 2 more answers
You have a job as a teacher. Your salary for the first year is $37,185.
tester [8842]
a) This represents a geometric sequence. b) c) The salary at the beginning of the fifth year will be $46,945.21. To clarify, my starting salary is $37,185. Should I receive a 6% raise each year, the salary for the following year will be: $37,185 x 1.06 = $39,416.10. Consequently, the salary after the second year will be: $39,416.10 x 1.06 = $41,781.07. Hence, the salary sequence will look like: $37,185, $39,416.10, $41,781.07, and so forth, demonstrating a consistent ratio of r = 1.06 for each term.
5 0
10 days ago
The computers of six faculty members in a certain department are to be replaced. Two of the faculty members have selected laptop
lawyer [9240]

Answer:

a. \frac{1}{15}

b. \frac{2}{5}

c. \frac{14}{15}

d. \frac{8}{15}

Step-by-step explanation:

There are four desktop computers and two laptops.

On a specific day, we will set up 2 of these computers.

To find:

a. What is the probability that both selected computers are laptops?

b. What is the probability that both computers are desktops?

c. What is the probability that at least one computer is a desktop?

d. What is the probability that at least one of each type of computer is included?

Solution:

Using the probability formula for event E:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

a. The number of successful outcomes for both computers being laptops = _2C_2 = 1

Total possible outcomes = 15

The needed probability is \frac{1}{15}.

b. The successful outcomes for both being desktop computers = _4C_2=6

Total possible outcomes = 15

The required probability is \frac{6}{15} = \frac{2}{5}.

c. For at least one desktop:

Two scenarios exist:

1. 1 desktop and 1 laptop:

Successful outcomes = _2C_1\times _4C_1 = 8

2. Both are desktops:

Successful outcomes = _4C_2=6

Total successful outcomes = 8 + 6 = 14

The needed probability is \frac{14}{15}.

d. 1 desktop and 1 laptop:

Successful outcomes = _2C_1\times _4C_1 = 8

Total outcomes = 15

The required probability is \frac{8}{15}.

8 0
21 day ago
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