A mail clerk found that the total weight of 155 packages was 815 pounds. if each of the packages weighed either 3 pounds or 8 po

a) q(p) = -15p + 300; b) R(p) = -15p² + 300p; c) C(p) = -30p + 1600; d) 1) P(p) = -15p² + 330p - 1600; d) 2) p = $11. To develop the demand equation, we plot the values of the cover charge against the number of guests per night for the given coordinates (9,165) and (10,150). The slope provides the relationship needed to formulate the linear equation relating guests and cover charge. The revenue function follows from multiplying price by guests, while the cost function encompasses overhead and beverage expenses associated with operational costs. The profitability equation emerges from subtracting costs from revenues, allowing us to determine the optimal entrance fee for maximum profit.

I think the answer is 42 feet.

Let x denote the count of $5 bills and y signify the count of $10 bills. It can be stated that "the number of $10 bills is twice the number of $5 bills." Thus, y is 2 times x. We can formulate an equation, y = 2x (equation 1). The total value of all bills amounts to $125, allowing us to create another equation: 5*(number of $5 bills) + 10*(number of $10 bills) = 125. That leads to the equation 5(x) + 10(y) = 125 (equation 2). By substituting y = 2x into equation 2, we get 5(x) + 10(2x) = 125. This simplifies to 5x + 20x = 125. Combining like terms yields 25x = 125. Dividing both sides by 25 results in x = 5. By substituting x = 5 in the first equation, we find y = 2(5) = 10. Consequently, there are 5 $5 bills and 10 $10 bills.

Answer:

The distance from the point (0,1,1) to the specified line is zero.

Step-by-step explanation:

Considering the parametric equations of the line,

x=2t, y=5-2t, z=1+t

In order to calculate the distance from (0,1,1), we must remove t from the equations above, such that

whose direction ratios are (l,m,n)=(3,2,-2) and the distance from point (a,b,c)=(0,1,1) is defined as

The distance between the point (0,1,1) and (1) amounts to zero. Therefore, the point (0,1,1) is located on the line (1).